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Answer
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$\sqrt{ 12 } + \dfrac{ 3 }{ \sqrt{ 3 } } - \dfrac{ 2 \sqrt{ 27 } }{ 3 }$
$\sqrt{ 3 }$
Calculate the value
$\sqrt{ \color{#FF6800}{ 12 } } + \dfrac { 3 } { \sqrt{ 3 } } - \dfrac { 2 \sqrt{ 27 } } { 3 }$
$ $ Organize the part that can be taken out of the radical sign inside the square root symbol $ $
$\color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 3 } } + \dfrac { 3 } { \sqrt{ 3 } } - \dfrac { 2 \sqrt{ 27 } } { 3 }$
$2 \sqrt{ 3 } + \color{#FF6800}{ \dfrac { 3 } { \sqrt{ 3 } } } - \dfrac { 2 \sqrt{ 27 } } { 3 }$
$ $ Calculate the expression $ $
$2 \sqrt{ 3 } + \sqrt{ \color{#FF6800}{ 3 } } - \dfrac { 2 \sqrt{ 27 } } { 3 }$
$2 \sqrt{ 3 } + \sqrt{ 3 } - \dfrac { \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 27 } } } { 3 }$
$ $ Simplify the expression $ $
$2 \sqrt{ 3 } + \sqrt{ 3 } - \dfrac { \color{#FF6800}{ 6 } \sqrt{ \color{#FF6800}{ 3 } } } { 3 }$
$2 \sqrt{ 3 } + \sqrt{ 3 } - \color{#FF6800}{ \dfrac { 6 \sqrt{ 3 } } { 3 } }$
$ $ Reduce the fraction $ $
$2 \sqrt{ 3 } + \sqrt{ 3 } - \left ( \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 3 } } \right )$
$\color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 3 } } + \sqrt{ 3 } \color{#FF6800}{ - } \left ( \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 3 } } \right )$
$ $ Remove the two numbers if the values are the same and the signs are different $ $
$\sqrt{ 3 }$
Solution search results
search-thumbnail-IUn of Radicals (Show your $sola1tion\right)$ 
$1$ $\dfrac {\sqrt{12} } {\sqrt{3} }$ $2$ $\dfrac {2\sqrt{5} } {3\sqrt{2} }$ $\dfrac {\sqrt{5} } {\sqrt [3.] {15} }$ $\bar{4.\dfrac {\sqrt{27} } {\sqrt{3} }} $ $5.\dfrac {8} {2\sqrt{2} }$ 
$=$ $=$ $=$ 
$=\sqrt{3} $ $\sqrt{} $ $=\sqrt{4} $ 
$=\dfrac {\sqrt{27} } {\sqrt{5} }$ $\dfrac {\sqrt{27} } {3}$ $\sqrt{9} $ $\sqrt{3} $
7th-9th grade
Algebra
search-thumbnail-dicals (Show your $solation\right)$ 
$2.\dfrac {2\sqrt{5} } {3\sqrt{2} }$ $3$ $\dfrac {\sqrt{5} } {\sqrt{15} }$ $4$ $\dfrac {\sqrt{27} } {\sqrt{3} }$ $5.$ $\dfrac {8} {2\sqrt{2} }$ 
$=$ $=$ 
$=\dfrac {\sqrt{27} } {\sqrt{3} }$ $=\dfrac {\sqrt{27} } {3}$ $\sqrt{a} $
7th-9th grade
Other
search-thumbnail-$11.$ Question $11$ 
Solve the $:$ $folloMlng'$ $0<θ<90^{°}$ 
$\left(1\right)$ $2sin^{2}θ=1\right)$ $\left(rac\left(3\right)\left(2\right)\right)$ 
$\left(11\right)$ $3tan^{2}θ+2=3$ 
$\left(111\right)cos^{2}θ$ $11rac\left(1\right)\left(4\right)\right)=$ 
$c\left(1\right)\left(4\right)\right)=11113c\left(1\right)\left(2\right)\right)$
10th-13th grade
Trigonometry
search-thumbnail-Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
search-thumbnail-The rationalizing factor of \sqrt{23} is 
$°$ $Options^{°}$ $0$ 
A 24 
23 
C \sqrt{23} 
D None of these
7th-9th grade
Other
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