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Formula
Solve the equation
Answer
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Graph
$y = \sqrt{ 0.002 }$
$y = x \sqrt{ 5 }$
$x$-intercept
$\left ( 0 , 0 \right )$
$y$-intercept
$\left ( 0 , 0 \right )$
$\sqrt{ 0.002 } = x \sqrt{ 5 }$
$x = \dfrac { 1 } { 50 }$
$ $ Solve a solution to $ x$
$\sqrt{ \color{#FF6800}{ 0.002 } } = x \sqrt{ 5 }$
$ $ Convert decimals to fractions $ $
$\sqrt{ \color{#FF6800}{ \dfrac { 1 } { 500 } } } = x \sqrt{ 5 }$
$\sqrt{ \color{#FF6800}{ \dfrac { 1 } { 500 } } } = x \sqrt{ 5 }$
$ $ Separate the radical sign from the denominator and numerator $ $
$\color{#FF6800}{ \dfrac { \sqrt{ 1 } } { \sqrt{ 500 } } } = x \sqrt{ 5 }$
$\dfrac { \sqrt{ \color{#FF6800}{ 1 } } } { \sqrt{ 500 } } = x \sqrt{ 5 }$
$n $ square root of 1 is 1 $ $
$\dfrac { \color{#FF6800}{ 1 } } { \sqrt{ 500 } } = x \sqrt{ 5 }$
$\dfrac { 1 } { \sqrt{ \color{#FF6800}{ 500 } } } = x \sqrt{ 5 }$
$ $ Organize the part that can be taken out of the radical sign inside the square root symbol $ $
$\dfrac { 1 } { \color{#FF6800}{ 10 } \sqrt{ \color{#FF6800}{ 5 } } } = x \sqrt{ 5 }$
$\dfrac { 1 } { 10 \sqrt{ 5 } } = \color{#FF6800}{ x } \sqrt{ \color{#FF6800}{ 5 } }$
$ $ Simplify the expression $ $
$\dfrac { 1 } { 10 \sqrt{ 5 } } = \sqrt{ \color{#FF6800}{ 5 } } \color{#FF6800}{ x }$
$\color{#FF6800}{ \dfrac { 1 } { 10 \sqrt{ 5 } } } = \sqrt{ 5 } x$
$ $ Calculate the expression $ $
$\color{#FF6800}{ \dfrac { \sqrt{ 5 } } { 50 } } = \sqrt{ 5 } x$
$\color{#FF6800}{ \dfrac { \sqrt{ 5 } } { 50 } } = \sqrt{ \color{#FF6800}{ 5 } } \color{#FF6800}{ x }$
$ $ Organize the expression $ $
$\sqrt{ \color{#FF6800}{ 5 } } \color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { \sqrt{ 5 } } { 50 } }$
$\sqrt{ \color{#FF6800}{ 5 } } \color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { \sqrt{ 5 } } { 50 } }$
$ $ Divide both sides by the same number $ $
$\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { \sqrt{ 5 } } { 50 \sqrt{ 5 } } }$
$x = \color{#FF6800}{ \dfrac { \sqrt{ 5 } } { 50 \sqrt{ 5 } } }$
$ $ Calculate the expression $ $
$x = \color{#FF6800}{ \dfrac { 1 } { 50 } }$
$ $ 그래프 보기 $ $
Graph
Solution search results
search-thumbnail-$.001$ $x$ $\dfrac {5} {0.002}x$ $1$ $=\dfrac {6} {100}x$ $=\dfrac {3} {5}x$ $1=5$
7th-9th grade
Other
search-thumbnail-$4-$ 
$\sqrt{} ^{\times 0.036\times 0.016\times 0.08}=7$ $0.002\times 0.0008\times 0.0002$ 
$\left($ $a$ $\right)$ $34$ $\left(b\right)$ (b) $36$
10th-13th grade
Other
search-thumbnail-$\left($ $1$ $2$ 
$9$ $\sqrt{\dfrac {0.009\times 0.036\times 0.016\times 0.08} {0.002\times 0.0008\times 0.0002}} $ is e 
$\sqrt{} ^{\times 0.036\times 0.016\times 0.08}$ $0.002\times 0.0008\times 0.0002$ बरा 
$\left($ $\right)$ $34$ 2.
10th-13th grade
Other
search-thumbnail-The rationalizing factor of \sqrt{23} is 
$°$ $Options^{°}$ $0$ 
A 24 
23 
C \sqrt{23} 
D None of these
7th-9th grade
Other
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