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Formula
Square root
Answer
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Find the approximate value
Answer
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$\sqrt[3]{ 256 }$
$4 \sqrt[ 3 ]{ 4 }$
Find the square root
$\sqrt[ 3 ]{ \color{#FF6800}{ 256 } }$
$ $ Do a factorization in prime factors for the integral number inside the radical sign $ $
$\sqrt[ 3 ]{ \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 8 } } }$
$\sqrt[ 3 ]{ \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 8 } } }$
$ $ Separate the part that can be taken out from the radical sign and the part that cannot be taken out $ $
$\sqrt[ 3 ]{ \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 6 } } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 2 } } }$
$\sqrt[ 3 ]{ \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 6 } } \times \color{#FF6800}{ 2 } ^ { 2 } }$
$ $ Separate the part that can be taken out of radical sign to different radical sign from the prime factor to the prime factor $ $
$\sqrt[ \color{#FF6800}{ 3 } ]{ \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 6 } } } \sqrt[ \color{#FF6800}{ 3 } ]{ \color{#FF6800}{ 2 } ^ { 2 } }$
$\sqrt[ \color{#FF6800}{ 3 } ]{ \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 6 } } } \sqrt[ 3 ]{ 2 ^ { 2 } }$
$ $ Get rid of the radical sign and change it to the denominator of the exponent $ $
$\color{#FF6800}{ 2 } ^ { \color{#FF6800}{ \frac { 6 } { 3 } } } \sqrt[ 3 ]{ 2 ^ { 2 } }$
$2 ^ { \color{#FF6800}{ \frac { 6 } { 3 } } } \sqrt[ 3 ]{ 2 ^ { 2 } }$
$ $ Reduce the fraction to the lowest term $ $
$2 ^ { \color{#FF6800}{ 2 } } \sqrt[ 3 ]{ 2 ^ { 2 } }$
$\color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 2 } } \sqrt[ 3 ]{ 2 ^ { 2 } }$
$ $ Calculate power $ $
$\color{#FF6800}{ 4 } \sqrt[ 3 ]{ 2 ^ { 2 } }$
$4 \sqrt[ 3 ]{ \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 2 } } }$
$ $ Calculate power $ $
$4 \sqrt[ 3 ]{ \color{#FF6800}{ 4 } }$
$\approx 6.3496$
Find the approximate value
$\sqrt[ \color{#FF6800}{ 3 } ]{ \color{#FF6800}{ 256 } }$
$ $ Find the approximate value of the square root $ $
$\approx \color{#FF6800}{ 6.3496 }$
Solution search results
search-thumbnail-$8\sqrt [3] {16} +\sqrt [3] {54} +\sqrt [3] {250} $ 
816 
d) $\sqrt{81} -8\sqrt [3] {216} +15\sqrt [3] {32} +\sqrt{225} $
7th-9th grade
Algebra
search-thumbnail-$\sqrt [3] {25.47} \times \sqrt [5] {342-2} $
7th-9th grade
Other
search-thumbnail-$\sqrt [3] {5} 4-$ $\sqrt [3] {25} 0-$ $\sqrt [3] {1b} =$
10th-13th grade
Calculus
search-thumbnail-$\left(\dfrac {5^{3}\times 2^{6}\right)^{\dfrac {1} {3}}\times \sqrt [3] {125} \times \sqrt [4] {256} } {25\times 64}$
7th-9th grade
Other
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