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Formula
Square root
Answer
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$\sqrt[ 4 ]{ 625 }$
$5$
Find the square root
$\sqrt[ 4 ]{ \color{#FF6800}{ 625 } }$
$ $ Do a factorization in prime factors for the integral number inside the radical sign $ $
$\sqrt[ 4 ]{ \color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 4 } } }$
$\sqrt[ \color{#FF6800}{ 4 } ]{ \color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 4 } } }$
$ $ Get rid of the radical sign and change it to the denominator of the exponent $ $
$\color{#FF6800}{ 5 } ^ { \color{#FF6800}{ \frac { 4 } { 4 } } }$
$5 ^ { \color{#FF6800}{ \frac { 4 } { 4 } } }$
$ $ Reduce the fraction to the lowest term $ $
$5 ^ { \color{#FF6800}{ 1 } }$
$5 ^ { \color{#FF6800}{ 1 } }$
$ $ If the exponent is 1, get rid of it as it is unnecessary $ $
$5$
Solution search results
search-thumbnail-$-3$ $\left(iii\right)$ $\left(\dfrac {169} {625}\longdiv{2}$
7th-9th grade
Algebra
search-thumbnail-$-3$ 
$y=\left(\sqrt [4] {\dfrac {81} {625}} $
10th-13th grade
Algebra
search-thumbnail-$A.$ Simplify the following. 
$10$ $\sqrt [4] {625} $ $=$ 
$2$ $\sqrt [10] {625} =$ $\sqrt [6] {8m^{9}n^{12}} $ 
$3$ $-$ $-$
7th-9th grade
Other
search-thumbnail-$17$ $S$ Simplify $\sqrt [4] {625x^{28}y^{32}} $
7th-9th grade
Other
search-thumbnail-The rationalizing factor of \sqrt{23} is 
$°$ $Options^{°}$ $0$ 
A 24 
23 
C \sqrt{23} 
D None of these
7th-9th grade
Other
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