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Solve the equation
Answer
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Graph
$y = \log _{ 8 } { \left( x \right) }$
$y = \dfrac { 1 } { 3 }$
$x$Intercept
$\left ( 1 , 0 \right )$
Asymptote
$x = 0$
$x = 2$
Solve the equation
$\log _{ \color{#FF6800}{ 8 } } { \left( \color{#FF6800}{ x } \right) } = \color{#FF6800}{ \dfrac { \color{#FF6800}{ 1 } } { \color{#FF6800}{ 3 } } }$
$ $ Find the interval that satisfies the basic condition of each formula $ $
$\log _{ \color{#FF6800}{ 8 } } { \left( \color{#FF6800}{ x } \right) } = \color{#FF6800}{ \dfrac { \color{#FF6800}{ 1 } } { \color{#FF6800}{ 3 } } } \left ( \text{However (or only)} \color{#FF6800}{ x } > \color{#FF6800}{ 0 } \right )$
$\log _{ \color{#FF6800}{ 8 } } { \left( \color{#FF6800}{ x } \right) } = \color{#FF6800}{ \dfrac { \color{#FF6800}{ 1 } } { \color{#FF6800}{ 3 } } } \left ( \text{However (or only)} x > 0 \right )$
$ $ Organize the equation using the logarithm definition $ $
$\color{#FF6800}{ x } = \color{#FF6800}{ 2 } \left ( \text{However (or only)} x > 0 \right )$
$\color{#FF6800}{ x } = \color{#FF6800}{ 2 } \left ( \text{However (or only)} \color{#FF6800}{ x } > \color{#FF6800}{ 0 } \right )$
$ $ Confirm if the solution exists in the domain $ $
$\color{#FF6800}{ x } = \color{#FF6800}{ 2 }$
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