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Formula
Calculate the value
Answer
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$\log_{ 6 } {\left( 12 \right)}$
$1 + \log _{ 6 } { \left( 2 \right) }$
Calculate the value
$\log _{ 6 } { \left( \color{#FF6800}{ 12 } \right) }$
$ $ Factor the antilogarithm with the expression in which $ 6 $ , that is the base, is included $ $
$\log _{ 6 } { \left( \color{#FF6800}{ 6 } \right) } + \log _{ 6 } { \left( \color{#FF6800}{ 2 } \right) }$
$\log _{ \color{#FF6800}{ 6 } } { \left( \color{#FF6800}{ 6 } \right) } + \log _{ 6 } { \left( 2 \right) }$
$ $ The logarithm is equal to 1 if a base is same as an antilogarithm $ $
$\color{#FF6800}{ 1 } + \log _{ 6 } { \left( 2 \right) }$
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