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Formula
Solve the equation
Answer
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Graph
$y = \left ( x + 2 \right ) \left ( x ^ { 2 } - 3 x + 4 \right )$
$y = 0$
$x$Intercept
$\left ( - 2 , 0 \right )$
$y$Intercept
$\left ( 0 , 8 \right )$
Derivative
$3 x ^ { 2 } - 2 x - 2$
Seconde derivative
$6 x - 2$
Local Minimum
$\left ( \dfrac { 1 } { 3 } + \dfrac { \sqrt{ 7 } } { 3 } , - \dfrac { 2 \sqrt{ 7 } } { 3 } - \left ( \dfrac { 1 } { 3 } + \dfrac { \sqrt{ 7 } } { 3 } \right ) ^ { 2 } + \left ( \dfrac { 1 } { 3 } + \dfrac { \sqrt{ 7 } } { 3 } \right ) ^ { 3 } + \dfrac { 22 } { 3 } \right )$
Local Maximum
$\left ( \dfrac { 1 } { 3 } - \dfrac { \sqrt{ 7 } } { 3 } , - \left ( \dfrac { 1 } { 3 } - \dfrac { \sqrt{ 7 } } { 3 } \right ) ^ { 2 } + \left ( \dfrac { 1 } { 3 } - \dfrac { \sqrt{ 7 } } { 3 } \right ) ^ { 3 } + \dfrac { 2 \sqrt{ 7 } } { 3 } + \dfrac { 22 } { 3 } \right )$
Point of inflection
$\left ( \dfrac { 1 } { 3 } , \dfrac { 196 } { 27 } \right )$
$\left( x+2 \right) \left( x ^{ 2 } -3x+4 \right) = 0$
$\begin{array} {l} x = - 2 \\ x = \dfrac { 3 + \sqrt{ 7 } i } { 2 } \\ x = \dfrac { 3 - \sqrt{ 7 } i } { 2 } \end{array}$
Solve the equation
$\left ( \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \right ) \left ( \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 4 } \right ) = \color{#FF6800}{ 0 }$
$ $ At least one factor should be 0 $ $
$\begin{array} {l} \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 2 } = \color{#FF6800}{ 0 } \\ \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 4 } = \color{#FF6800}{ 0 } \end{array}$
$\begin{array} {l} \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 2 } = \color{#FF6800}{ 0 } \\ \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 4 } = \color{#FF6800}{ 0 } \end{array}$
$ $ Solve each equation $ $
$\begin{array} {l} \color{#FF6800}{ x } = \color{#FF6800}{ - } \color{#FF6800}{ 2 } \\ \color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 3 + \sqrt{ 7 } i } { 2 } } \\ \color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 3 - \sqrt{ 7 } i } { 2 } } \end{array}$
$ $ 그래프 보기 $ $
Graph
Solution search results
search-thumbnail-Question $4\left(1$ point) 
Given that $\left(x+2\right)$ $15a$ factor of $P\left(x\right)=3x^{3}+3x^{2}-10x-8,$ 
find the corresponding factor, $f\left(x\right)$ such that 
$3x^{3}+3x^{2}$ $-10x-8=\left(x+2\right)$ $f\left(x\right)$ 
$①$ $-3x^{2}+2x-1$ 
$3x^{2}-3x-4$ 
$3x^{2}-3x+1$ 
$-3x^{2}-3x+4$ 
$-3$
10th-13th grade
Algebra
search-thumbnail-If the sum of two consecutive 
numbers is $45$ and one number is $X$ 
.This statement in the form of 
equation $1s:$ 
$\left(1$ Point) $\right)$ 
$○5x+1$ $1eft\left(x+1$ $r1gnt\right)=45s$ 
$○sx+1ef\left(x+2$ $r1gnt\right)=145s$ 
$sx+1x=45s$
7th-9th grade
Algebra
search-thumbnail-$s|ef\left(-1n$ $\left($ }\right)^{50}\ $\right)$ \ | | is\ equal\ to\ $S$ 
$s1S$ 
$S-1S$ 
$s2S$ 
$s50s$
7th-9th grade
Other
search-thumbnail-Given the set of ordered pairs $\left(\left(-7.0\right),\left(-6,5\right),\left(-5,-3\right),\left(-1,2\right)$ $\left(1,6\right),\left(2,-2\right)$ $\left(5,3\right)\left(7,-8\right)\right)$ 
Find f(7)fAleft(7\right) 
O a 
O b -8 
6. 
$5$
7th-9th grade
Algebra
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