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Calculate the value
Answer
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$\left( -5a ^{ 2 } b \right) \div \left( -10ab \right) \times \left( -2ab ^{ 3 } \right) ^{ 2 }$
$2 a ^ { 3 } b ^ { 6 }$
Arrange the rational expression
$\left ( \color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ b } \right ) \color{#FF6800}{ \div } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 10 } \color{#FF6800}{ a } \color{#FF6800}{ b } \right ) \color{#FF6800}{ \times } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ a } \color{#FF6800}{ b } ^ { \color{#FF6800}{ 3 } } \right ) ^ { \color{#FF6800}{ 2 } }$
$ $ Get rid of unnecessary parentheses $ $
$\color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ b } \color{#FF6800}{ \div } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 10 } \color{#FF6800}{ a } \color{#FF6800}{ b } \right ) \color{#FF6800}{ \times } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ a } \color{#FF6800}{ b } ^ { \color{#FF6800}{ 3 } } \right ) ^ { \color{#FF6800}{ 2 } }$
$\color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ b } \color{#FF6800}{ \div } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 10 } \color{#FF6800}{ a } \color{#FF6800}{ b } \right ) \color{#FF6800}{ \times } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ a } \color{#FF6800}{ b } ^ { \color{#FF6800}{ 3 } } \right ) ^ { \color{#FF6800}{ 2 } }$
$ $ Calculate the multiplication expression $ $
$\color{#FF6800}{ 2 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 3 } } \color{#FF6800}{ b } ^ { \color{#FF6800}{ 6 } }$
Solution search results
search-thumbnail-$s|ef\left(-1n$ $\left($ }\right)^{50}\ $\right)$ \ | | is\ equal\ to\ $S$ $s1S$ $S-1S$ $s2S$ $s50s$
7th-9th grade
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search-thumbnail-The is the statement of the Mean Value Theorem from your $te\times tb00k$ $Tneoren$ $m4.5$ $Ne8n$ Value Theorem Let f be continuous over $leclose$ interval $\left(a.b\right)aod$ $i$ $eo$ $xd$ $csnlc$ $\left(ab\right)$ $mmd$ exists at least one point cE $\left(a.b\right)$ $si1dhtba$ $f^{'}\left(c\right)=\dfrac {f\left(b\right)-f\left(a\right)} {b-a}$ What is the geometric interpretation of the conclusion of the theorem? O The tangent line to the graph of \(f\left(x\right)\) at $l\left(c1\right)$ is parallel to the secant line connecting \(\left(a,f\left(a\right)\right)\) and \(\left(b,f\left(b\right)\right)\). O The tangent line to the graph of $\left(f\left(lef\left(x\left(right\right)$ at \(c\) is the secant line connecting \(\left(a,f\left(a\right)\right)\) $ana$ \(\left(b,f\left(b\right)\right)\). O The tangent line to the graph $of$ $\left(f\left(leF\left(x\left(right\right)\left(\right)at1\left(c1\right)is$ perpendicular to the secant line connecting \(\left(a,f\left(a\right)\right)\) and A(\left(b,f\left(b\right)\right)\). O The tangent line to the graph of $\left(fleH\left(x\right)nght\right)\right)\right)$ $at$ $\left(c\right)\right)ishoizonta|$ $Tnere$ is more than one tangent line to the graph $0no$ $\left(flcf\left(x\right)night\right)\left($ $at1\left(c1\right)$
Calculus
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