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Formula
Calculate the value
$\left( 3+ \sqrt{ 3 } \right) \left( 3- \sqrt{ 3 } \right)$
$6$
Calculate the value
$\left ( \color{#FF6800}{ 3 } \color{#FF6800}{ + } \sqrt{ \color{#FF6800}{ 3 } } \right ) \left ( \color{#FF6800}{ 3 } \color{#FF6800}{ - } \sqrt{ \color{#FF6800}{ 3 } } \right )$
 Expand the expression using $\left(a - b\right)\left(a + b\right) = a^{2} - b^{2}$
$\color{#FF6800}{ 3 } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \left ( \sqrt{ \color{#FF6800}{ 3 } } \right ) ^ { \color{#FF6800}{ 2 } }$
$\color{#FF6800}{ 3 } ^ { \color{#FF6800}{ 2 } } - \left ( \sqrt{ 3 } \right ) ^ { 2 }$
 Calculate power 
$\color{#FF6800}{ 9 } - \left ( \sqrt{ 3 } \right ) ^ { 2 }$
$9 - \left ( \sqrt{ \color{#FF6800}{ 3 } } \right ) ^ { \color{#FF6800}{ 2 } }$
 If you square the radical sign, it will disappear 
$9 - \color{#FF6800}{ 3 }$
$\color{#FF6800}{ 9 } \color{#FF6800}{ - } \color{#FF6800}{ 3 }$
 Subtract $3$ from $9$
$\color{#FF6800}{ 6 }$
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