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Formula
Calculate the value
Answer
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Use the synthetic division to find the quotient and the remainder
Answer
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$\left( 2x ^{ 3 } -3x ^{ 2 } +3x+1 \right) \div \left( 2x-1 \right)$
$\dfrac { 2 x ^ { 3 } - 3 x ^ { 2 } + 3 x + 1 } { 2 x - 1 }$
Arrange the rational expression
$\left ( \color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 3 } } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) \color{#FF6800}{ \div } \left ( \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right )$
$ $ Calculate the multiplication expression $ $
$\color{#FF6800}{ \dfrac { 2 x ^ { 3 } - 3 x ^ { 2 } + 3 x + 1 } { 2 x - 1 } }$
$ $ Quotient $ : x ^ { 2 } - x + 1 \\ $ Remainder $ : 2$
Use the synthetic division to find the quotient and the remainder
$\left ( \color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 3 } } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) \color{#FF6800}{ \div } \left ( \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right )$
$ $ Divide $ 2 x ^ { 3 } - 3 x ^ { 2 } + 3 x + 1 $ by $ 2 x - 1 $ using the synthetic division $ $
$ $ Quotient $ : x ^ { 2 } - x + 1 \\ $ Remainder $ : 2$
Solution search results
search-thumbnail-$=$ $23$ The equation whose roots are squares of the roots of $x^{4}+x^{3}+2x^{2}+x+1=0$ is $1\right)$ $x^{4}-3x^{3}+4x^{2}+3x+1=0$ $2\right)$ $x^{4}+3x^{3}+4x^{2}+3x+1=0$ $3\right)$ $x^{4}-3x^{3}-4x^{2}+3x+1=0$ $4\right)$ $x^{4}-3x^{3}-4x^{2}-3x+1=0$
10th-13th grade
Algebra
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search-thumbnail-The is the statement of the Mean Value Theorem from your $te\times tb00k$ $Tneoren$ $m4.5$ $Ne8n$ Value Theorem Let f be continuous over $leclose$ interval $\left(a.b\right)aod$ $i$ $eo$ $xd$ $csnlc$ $\left(ab\right)$ $mmd$ exists at least one point cE $\left(a.b\right)$ $si1dhtba$ $f^{'}\left(c\right)=\dfrac {f\left(b\right)-f\left(a\right)} {b-a}$ What is the geometric interpretation of the conclusion of the theorem? O The tangent line to the graph of \(f\left(x\right)\) at $l\left(c1\right)$ is parallel to the secant line connecting \(\left(a,f\left(a\right)\right)\) and \(\left(b,f\left(b\right)\right)\). O The tangent line to the graph of $\left(f\left(lef\left(x\left(right\right)$ at \(c\) is the secant line connecting \(\left(a,f\left(a\right)\right)\) $ana$ \(\left(b,f\left(b\right)\right)\). O The tangent line to the graph $of$ $\left(f\left(leF\left(x\left(right\right)\left(\right)at1\left(c1\right)is$ perpendicular to the secant line connecting \(\left(a,f\left(a\right)\right)\) and A(\left(b,f\left(b\right)\right)\). O The tangent line to the graph of $\left(fleH\left(x\right)nght\right)\right)\right)$ $at$ $\left(c\right)\right)ishoizonta|$ $Tnere$ is more than one tangent line to the graph $0no$ $\left(flcf\left(x\right)night\right)\left($ $at1\left(c1\right)$
Calculus
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search-thumbnail-$g\left(x\right)=3x+1$ $f\left(x\right)$ $=x^{3}$ $-3x^{2}$ Find $\left(g+f\right)\left(x\right)$ $0x^{3}-3x^{4}+3x+1$ $○x+1$ $0-x^{3}+3x^{2}+3x+1$ $x^{3}$ $-3x^{2}+3x+1$
Other
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search-thumbnail-Jika $f\left(x\right)=x^{2}-x+2$ dan $g\left(x\right)=2x^{2}+x-1$ maka $f\left(x\right).g\left(x\right)$ adalah ... A. $2x^{5}-x^{4}+3x^{3}-3x^{2}+3x-2$ 2 B. $2x^{5}-x^{4}-3x^{3}+3x^{2}-3x+2$ C. $2x^{5}+x^{4}-3x^{3}-3x^{2}+3x+2$ D.2x5 $2x^{5}+x^{4}-3x^{3}+3x^{2}+3x-2$ E. $2x^{5}+x^{4}+3x^{3}-3x^{2}+3x-2$
10th-13th grade
Trigonometry
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