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Formula
Calculate the value
Answer
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Use the synthetic division to find the quotient and the remainder
Answer
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$\left( 2x ^{ 3 } +3x ^{ 2 } +2x-1 \right) \div \left( x ^{ 2 } +x+1 \right)$
$\dfrac { 2 x ^ { 3 } + 3 x ^ { 2 } + 2 x - 1 } { x ^ { 2 } + x + 1 }$
Arrange the rational expression
$\left ( \color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 3 } } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \color{#FF6800}{ \div } \left ( \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right )$
$ $ Calculate the multiplication expression $ $
$\color{#FF6800}{ \dfrac { 2 x ^ { 3 } + 3 x ^ { 2 } + 2 x - 1 } { x ^ { 2 } + x + 1 } }$
$ $ Quotient $ : 2 x + 1 \\ $ Remainder $ : - x - 2$
Use the synthetic division to find the quotient and the remainder
$\left ( \color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 3 } } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \color{#FF6800}{ \div } \left ( \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right )$
$ $ Divide $ 2 x ^ { 3 } + 3 x ^ { 2 } + 2 x - 1 $ by $ x ^ { 2 } + x + 1 $ using the synthetic division $ $
$ $ Quotient $ : 2 x + 1 \\ $ Remainder $ : - x - 2$
Solution search results
search-thumbnail-Perform division of polynomials using long division. 
$\left(3x^{4}+4-10x+7x^{3}\right)\div \left(3x-2\right)$ 
$2x^{3}+3x^{2}+2x-2$ 
$x^{3}+3x^{2}+2x-2$ 
$x^{3}-3x^{2}+2x-2$ 
$x^{3}+3x^{2}+2x-2$
10th-13th grade
Other
search-thumbnail-$p\left(x\right)=2x^{3}+x^{2}+2x-1,g\left(x\right)=x+1$ 
$\left(x\right)=x^{3}+3x^{2}+3x+1.g\left(x\right)=x+2$ 
$\left(x\right)=x^{3}-4x^{2}+x+6,s\left(x\right)=x-3$
10th-13th grade
Other
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