Symbol

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Formula
Number of solution
Relationship between roots and coefficients
Graph
$y = \left ( 24 - x \right ) \left ( 16 - 2 x \right )$
$y = 210$
$x$Intercept
$\left ( 8 , 0 \right )$, $\left ( 24 , 0 \right )$
$y$Intercept
$\left ( 0 , 384 \right )$
$\left( 24-x \right) \left( 16-2x \right) = 210$
$\begin{array} {l} x = 29 \\ x = 3 \end{array}$
Find solution by method of factorization
$\left ( 24 - x \right ) \left ( 16 - 2 x \right ) = \color{#FF6800}{ 210 }$
 Move the expression to the left side and change the symbol 
$\left ( 24 - x \right ) \left ( 16 - 2 x \right ) - 210 = 0$
$\left ( \color{#FF6800}{ 24 } \color{#FF6800}{ - } \color{#FF6800}{ x } \right ) \left ( \color{#FF6800}{ 16 } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } \right ) \color{#FF6800}{ - } \color{#FF6800}{ 210 } = 0$
 Expand the expression 
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 64 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 174 } = 0$
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 64 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 174 } = 0$
$acx^{2} + \left(ad + bc\right)x +bd = \left(ax + b\right)\left(cx+d\right)$
$\color{#FF6800}{ 2 } \left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 29 } \right ) \left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \right ) = 0$
$\color{#FF6800}{ 2 } \left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 29 } \right ) \left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \right ) = \color{#FF6800}{ 0 }$
 If the product of the factor is 0, at least one factor should be 0 
$\begin{array} {l} \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 29 } = \color{#FF6800}{ 0 } \\ \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 3 } = \color{#FF6800}{ 0 } \end{array}$
$\begin{array} {l} \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 29 } = \color{#FF6800}{ 0 } \\ \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 3 } = \color{#FF6800}{ 0 } \end{array}$
 Solve the equation to find $x$
$\begin{array} {l} \color{#FF6800}{ x } = \color{#FF6800}{ 29 } \\ \color{#FF6800}{ x } = \color{#FF6800}{ 3 } \end{array}$
$\begin{array} {l} x = 29 \\ x = 3 \end{array}$
Solve quadratic equations using the square root
$\left ( \color{#FF6800}{ 24 } \color{#FF6800}{ - } \color{#FF6800}{ x } \right ) \left ( \color{#FF6800}{ 16 } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } \right ) = 210$
 Organize the expression 
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 64 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 384 } = 210$
$2 x ^ { 2 } - 64 x + 384 = \color{#FF6800}{ 210 }$
 Move the expression to the left side and change the symbol 
$2 x ^ { 2 } - 64 x + 384 \color{#FF6800}{ - } \color{#FF6800}{ 210 } = 0$
$2 x ^ { 2 } - 64 x + \color{#FF6800}{ 384 } \color{#FF6800}{ - } \color{#FF6800}{ 210 } = 0$
 Subtract $210$ from $384$
$2 x ^ { 2 } - 64 x + \color{#FF6800}{ 174 } = 0$
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 64 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 174 } = \color{#FF6800}{ 0 }$
 Divide both sides by the coefficient of the leading highest term 
$\color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 32 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 87 } = \color{#FF6800}{ 0 }$
$\color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 32 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 87 } = \color{#FF6800}{ 0 }$
 Convert the quadratic expression on the left side to a perfect square format 
$\left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 16 } \right ) ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \color{#FF6800}{ 87 } \color{#FF6800}{ - } \color{#FF6800}{ 16 } ^ { \color{#FF6800}{ 2 } } = \color{#FF6800}{ 0 }$
$\left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 16 } \right ) ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \color{#FF6800}{ 87 } \color{#FF6800}{ - } \color{#FF6800}{ 16 } ^ { \color{#FF6800}{ 2 } } = \color{#FF6800}{ 0 }$
 Organize the expression 
$\left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 16 } \right ) ^ { \color{#FF6800}{ 2 } } = \color{#FF6800}{ 169 }$
$\left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 16 } \right ) ^ { \color{#FF6800}{ 2 } } = \color{#FF6800}{ 169 }$
 Solve quadratic equations using the square root 
$\color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 16 } = \pm \sqrt{ \color{#FF6800}{ 169 } }$
$\color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 16 } = \pm \sqrt{ \color{#FF6800}{ 169 } }$
 Solve a solution to $x$
$\color{#FF6800}{ x } = \pm \color{#FF6800}{ 13 } \color{#FF6800}{ + } \color{#FF6800}{ 16 }$
$\color{#FF6800}{ x } = \pm \color{#FF6800}{ 13 } \color{#FF6800}{ + } \color{#FF6800}{ 16 }$
 Separate the answer 
$\begin{array} {l} \color{#FF6800}{ x } = \color{#FF6800}{ 16 } \color{#FF6800}{ + } \color{#FF6800}{ 13 } \\ \color{#FF6800}{ x } = \color{#FF6800}{ 16 } \color{#FF6800}{ - } \color{#FF6800}{ 13 } \end{array}$
$\begin{array} {l} \color{#FF6800}{ x } = \color{#FF6800}{ 16 } \color{#FF6800}{ + } \color{#FF6800}{ 13 } \\ \color{#FF6800}{ x } = \color{#FF6800}{ 16 } \color{#FF6800}{ - } \color{#FF6800}{ 13 } \end{array}$
 Organize the expression 
$\begin{array} {l} \color{#FF6800}{ x } = \color{#FF6800}{ 29 } \\ \color{#FF6800}{ x } = \color{#FF6800}{ 3 } \end{array}$
$\begin{array} {l} x = 29 \\ x = 3 \end{array}$
$\left ( \color{#FF6800}{ 24 } \color{#FF6800}{ - } \color{#FF6800}{ x } \right ) \left ( \color{#FF6800}{ 16 } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } \right ) = 210$
 Organize the expression 
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 64 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 384 } = 210$
$2 x ^ { 2 } - 64 x + 384 = \color{#FF6800}{ 210 }$
 Move the expression to the left side and change the symbol 
$2 x ^ { 2 } - 64 x + 384 \color{#FF6800}{ - } \color{#FF6800}{ 210 } = 0$
$2 x ^ { 2 } - 64 x + \color{#FF6800}{ 384 } \color{#FF6800}{ - } \color{#FF6800}{ 210 } = 0$
 Subtract $210$ from $384$
$2 x ^ { 2 } - 64 x + \color{#FF6800}{ 174 } = 0$
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 64 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 174 } = 0$
 Bind the expressions with the common factor $2$
$\color{#FF6800}{ 2 } \left ( \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 32 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 87 } \right ) = 0$
$\color{#FF6800}{ 2 } \left ( \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 32 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 87 } \right ) = \color{#FF6800}{ 0 }$
 Divide both sides by $2$
$\color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 32 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 87 } = \color{#FF6800}{ 0 }$
$x = \dfrac { \color{#FF6800}{ - } \left ( \color{#FF6800}{ - } 32 \right ) \pm \sqrt{ \left ( - 32 \right ) ^ { 2 } - 4 \times 1 \times 87 } } { 2 \times 1 }$
 Simplify Minus 
$x = \dfrac { 32 \pm \sqrt{ \left ( - 32 \right ) ^ { 2 } - 4 \times 1 \times 87 } } { 2 \times 1 }$
$x = \dfrac { 32 \pm \sqrt{ \left ( \color{#FF6800}{ - } \color{#FF6800}{ 32 } \right ) ^ { \color{#FF6800}{ 2 } } - 4 \times 1 \times 87 } } { 2 \times 1 }$
 Remove negative signs because negative numbers raised to even powers are positive 
$x = \dfrac { 32 \pm \sqrt{ 32 ^ { 2 } - 4 \times 1 \times 87 } } { 2 \times 1 }$
$\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 32 \pm \sqrt{ 32 ^ { 2 } - 4 \times 1 \times 87 } } { 2 \times 1 } }$
 Organize the expression 
$\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 32 \pm \sqrt{ 676 } } { 2 \times 1 } }$
$x = \dfrac { 32 \pm \sqrt{ \color{#FF6800}{ 676 } } } { 2 \times 1 }$
 Organize the part that can be taken out of the radical sign inside the square root symbol 
$x = \dfrac { 32 \pm \color{#FF6800}{ 26 } } { 2 \times 1 }$
$x = \dfrac { 32 \pm 26 } { 2 \color{#FF6800}{ \times } \color{#FF6800}{ 1 } }$
 Multiplying any number by 1 does not change the value 
$x = \dfrac { 32 \pm 26 } { \color{#FF6800}{ 2 } }$
$\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 32 \pm 26 } { 2 } }$
 Separate the answer 
$\begin{array} {l} \color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 32 + 26 } { 2 } } \\ \color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 32 - 26 } { 2 } } \end{array}$
$\begin{array} {l} x = \dfrac { \color{#FF6800}{ 32 } \color{#FF6800}{ + } \color{#FF6800}{ 26 } } { 2 } \\ x = \dfrac { 32 - 26 } { 2 } \end{array}$
 Add $32$ and $26$
$\begin{array} {l} x = \dfrac { \color{#FF6800}{ 58 } } { 2 } \\ x = \dfrac { 32 - 26 } { 2 } \end{array}$
$\begin{array} {l} x = \color{#FF6800}{ \dfrac { 58 } { 2 } } \\ x = \dfrac { 32 - 26 } { 2 } \end{array}$
 Do the reduction of the fraction format 
$\begin{array} {l} x = \color{#FF6800}{ \dfrac { 29 } { 1 } } \\ x = \dfrac { 32 - 26 } { 2 } \end{array}$
$\begin{array} {l} x = \color{#FF6800}{ \dfrac { 29 } { 1 } } \\ x = \dfrac { 32 - 26 } { 2 } \end{array}$
 Reduce the fraction to the lowest term 
$\begin{array} {l} x = \color{#FF6800}{ 29 } \\ x = \dfrac { 32 - 26 } { 2 } \end{array}$
$\begin{array} {l} x = 29 \\ x = \dfrac { \color{#FF6800}{ 32 } \color{#FF6800}{ - } \color{#FF6800}{ 26 } } { 2 } \end{array}$
 Subtract $26$ from $32$
$\begin{array} {l} x = 29 \\ x = \dfrac { \color{#FF6800}{ 6 } } { 2 } \end{array}$
$\begin{array} {l} x = 29 \\ x = \color{#FF6800}{ \dfrac { 6 } { 2 } } \end{array}$
 Do the reduction of the fraction format 
$\begin{array} {l} x = 29 \\ x = \color{#FF6800}{ \dfrac { 3 } { 1 } } \end{array}$
$\begin{array} {l} x = 29 \\ x = \color{#FF6800}{ \dfrac { 3 } { 1 } } \end{array}$
 Reduce the fraction to the lowest term 
$\begin{array} {l} x = 29 \\ x = \color{#FF6800}{ 3 } \end{array}$
 2 real roots 
Find the number of solutions
$\left ( \color{#FF6800}{ 24 } \color{#FF6800}{ - } \color{#FF6800}{ x } \right ) \left ( \color{#FF6800}{ 16 } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } \right ) = 210$
 Organize the expression 
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 64 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 384 } = 210$
$2 x ^ { 2 } - 64 x + 384 = \color{#FF6800}{ 210 }$
 Move the expression to the left side and change the symbol 
$2 x ^ { 2 } - 64 x + 384 \color{#FF6800}{ - } \color{#FF6800}{ 210 } = 0$
$2 x ^ { 2 } - 64 x + \color{#FF6800}{ 384 } \color{#FF6800}{ - } \color{#FF6800}{ 210 } = 0$
 Subtract $210$ from $384$
$2 x ^ { 2 } - 64 x + \color{#FF6800}{ 174 } = 0$
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 64 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 174 } = \color{#FF6800}{ 0 }$
 Determine the number of roots using discriminant, $D=b^{2}-4ac$ from quadratic equation, $ax^{2}+bx+c=0$
$\color{#FF6800}{ D } = \left ( \color{#FF6800}{ - } \color{#FF6800}{ 64 } \right ) ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } \color{#FF6800}{ \times } \color{#FF6800}{ 174 }$
$D = \left ( \color{#FF6800}{ - } \color{#FF6800}{ 64 } \right ) ^ { \color{#FF6800}{ 2 } } - 4 \times 2 \times 174$
 Remove negative signs because negative numbers raised to even powers are positive 
$D = 64 ^ { 2 } - 4 \times 2 \times 174$
$D = \color{#FF6800}{ 64 } ^ { \color{#FF6800}{ 2 } } - 4 \times 2 \times 174$
 Calculate power 
$D = \color{#FF6800}{ 4096 } - 4 \times 2 \times 174$
$D = 4096 \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } \color{#FF6800}{ \times } \color{#FF6800}{ 174 }$
 Multiply the numbers 
$D = 4096 \color{#FF6800}{ - } \color{#FF6800}{ 1392 }$
$D = \color{#FF6800}{ 4096 } \color{#FF6800}{ - } \color{#FF6800}{ 1392 }$
 Subtract $1392$ from $4096$
$D = \color{#FF6800}{ 2704 }$
$\color{#FF6800}{ D } = \color{#FF6800}{ 2704 }$
 Since $D>0$ , the number of real root of the following quadratic equation is 2 
 2 real roots 
$\alpha + \beta = 32 , \alpha \beta = 87$
Find the sum and product of the two roots of the quadratic equation
$\left ( \color{#FF6800}{ 24 } \color{#FF6800}{ - } \color{#FF6800}{ x } \right ) \left ( \color{#FF6800}{ 16 } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } \right ) = 210$
 Organize the expression 
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 64 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 384 } = 210$
$2 x ^ { 2 } - 64 x + 384 = \color{#FF6800}{ 210 }$
 Move the expression to the left side and change the symbol 
$2 x ^ { 2 } - 64 x + 384 \color{#FF6800}{ - } \color{#FF6800}{ 210 } = 0$
$2 x ^ { 2 } - 64 x + \color{#FF6800}{ 384 } \color{#FF6800}{ - } \color{#FF6800}{ 210 } = 0$
 Subtract $210$ from $384$
$2 x ^ { 2 } - 64 x + \color{#FF6800}{ 174 } = 0$
$\color{#FF6800}{ 2 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 64 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 174 } = \color{#FF6800}{ 0 }$
 In the quadratic equation $ax^{2}+bx+c=0$ , if the two roots are $\alpha, \beta$ , then it is $\alpha + \beta =-\dfrac{b}{a}$ , $\alpha\times\beta=\dfrac{c}{a}$
$\color{#FF6800}{ \alpha } \color{#FF6800}{ + } \color{#FF6800}{ \beta } = \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { - 64 } { 2 } } , \color{#FF6800}{ \alpha } \color{#FF6800}{ \beta } = \color{#FF6800}{ \dfrac { 174 } { 2 } }$
$\alpha + \beta = \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { - 64 } { 2 } } , \alpha \beta = \dfrac { 174 } { 2 }$
 Solve the sign of a fraction with a negative sign 
$\alpha + \beta = \color{#FF6800}{ \dfrac { 64 } { 2 } } , \alpha \beta = \dfrac { 174 } { 2 }$
$\alpha + \beta = \color{#FF6800}{ \dfrac { 64 } { 2 } } , \alpha \beta = \dfrac { 174 } { 2 }$
 Reduce the fraction 
$\alpha + \beta = \color{#FF6800}{ 32 } , \alpha \beta = \dfrac { 174 } { 2 }$
$\alpha + \beta = 32 , \alpha \beta = \color{#FF6800}{ \dfrac { 174 } { 2 } }$
 Reduce the fraction 
$\alpha + \beta = 32 , \alpha \beta = \color{#FF6800}{ 87 }$
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