Calculator search results

Formula
Expand the expression
Answer
circle-check-icon
expand-arrow-icon
expand-arrow-icon
Factorize the expression
Answer
circle-check-icon
expand-arrow-icon
expand-arrow-icon
expand-arrow-icon
$\left( 1-c \right) \left( 1-a \right) \left( 1-b \right)$
$- a b c + a b + a c - a + b c - b - c + 1$
Organize polynomials
$\left ( \color{#FF6800}{ 1 } \color{#FF6800}{ - } \color{#FF6800}{ c } \right ) \left ( 1 - a \right ) \left ( 1 - b \right )$
$ $ Sort the polynomial expressions in descending order $ $
$\left ( \color{#FF6800}{ - } \color{#FF6800}{ c } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) \left ( 1 - a \right ) \left ( 1 - b \right )$
$\left ( - c + 1 \right ) \left ( \color{#FF6800}{ 1 } \color{#FF6800}{ - } \color{#FF6800}{ a } \right ) \left ( 1 - b \right )$
$ $ Sort the polynomial expressions in descending order $ $
$\left ( - c + 1 \right ) \left ( \color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) \left ( 1 - b \right )$
$\left ( - c + 1 \right ) \left ( - a + 1 \right ) \left ( \color{#FF6800}{ 1 } \color{#FF6800}{ - } \color{#FF6800}{ b } \right )$
$ $ Sort the polynomial expressions in descending order $ $
$\left ( - c + 1 \right ) \left ( - a + 1 \right ) \left ( \color{#FF6800}{ - } \color{#FF6800}{ b } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right )$
$\left ( \color{#FF6800}{ - } \color{#FF6800}{ c } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) \left ( \color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) \left ( - b + 1 \right )$
$ $ Organize the expression with the distributive law $ $
$\left ( \color{#FF6800}{ a } \color{#FF6800}{ c } \color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ c } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) \left ( - b + 1 \right )$
$\left ( \color{#FF6800}{ a } \color{#FF6800}{ c } \color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ c } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) \left ( \color{#FF6800}{ - } \color{#FF6800}{ b } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right )$
$ $ Organize the expression with the distributive law $ $
$\color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ b } \color{#FF6800}{ c } \color{#FF6800}{ + } \color{#FF6800}{ a } \color{#FF6800}{ b } \color{#FF6800}{ + } \color{#FF6800}{ a } \color{#FF6800}{ c } \color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ b } \color{#FF6800}{ c } \color{#FF6800}{ - } \color{#FF6800}{ b } \color{#FF6800}{ - } \color{#FF6800}{ c } \color{#FF6800}{ + } \color{#FF6800}{ 1 }$
$- \left ( a - 1 \right ) \left ( b - 1 \right ) \left ( c - 1 \right )$
Arrange the expression in the form of factorization..
$\left ( \color{#FF6800}{ 1 } \color{#FF6800}{ - } \color{#FF6800}{ c } \right ) \left ( 1 - a \right ) \left ( 1 - b \right )$
$ $ Expand the expression $ $
$\left ( \color{#FF6800}{ - } \color{#FF6800}{ c } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) \left ( 1 - a \right ) \left ( 1 - b \right )$
$\left ( \color{#FF6800}{ - } \color{#FF6800}{ c } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) \left ( 1 - a \right ) \left ( 1 - b \right )$
$ $ Bind the expressions with the common factor $ - 1$
$\color{#FF6800}{ - } \left ( \color{#FF6800}{ c } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \left ( 1 - a \right ) \left ( 1 - b \right )$
$- \left ( c - 1 \right ) \left ( \color{#FF6800}{ 1 } \color{#FF6800}{ - } \color{#FF6800}{ a } \right ) \left ( 1 - b \right )$
$ $ Expand the expression $ $
$- \left ( c - 1 \right ) \left ( \color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) \left ( 1 - b \right )$
$- \left ( c - 1 \right ) \left ( \color{#FF6800}{ - } \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) \left ( 1 - b \right )$
$ $ Bind the expressions with the common factor $ - 1$
$- \left ( c - 1 \right ) \times \left ( \color{#FF6800}{ - } \left ( \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \right ) \left ( 1 - b \right )$
$- \left ( c - 1 \right ) \times \left ( - \left ( a - 1 \right ) \right ) \left ( \color{#FF6800}{ 1 } \color{#FF6800}{ - } \color{#FF6800}{ b } \right )$
$ $ Expand the expression $ $
$- \left ( c - 1 \right ) \times \left ( - \left ( a - 1 \right ) \right ) \left ( \color{#FF6800}{ - } \color{#FF6800}{ b } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right )$
$- \left ( c - 1 \right ) \times \left ( - \left ( a - 1 \right ) \right ) \left ( \color{#FF6800}{ - } \color{#FF6800}{ b } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right )$
$ $ Bind the expressions with the common factor $ - 1$
$- \left ( c - 1 \right ) \times \left ( - \left ( a - 1 \right ) \right ) \times \left ( \color{#FF6800}{ - } \left ( \color{#FF6800}{ b } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \right )$
$\color{#FF6800}{ - } \left ( c - 1 \right ) \times \left ( \color{#FF6800}{ - } \left ( a - 1 \right ) \right ) \times \left ( \color{#FF6800}{ - } \left ( b - 1 \right ) \right )$
$ $ If you multiply negative numbers by odd numbers, move the (-) sign forward $ $
$- \left ( c - 1 \right ) \left ( a - 1 \right ) \left ( b - 1 \right )$
$\color{#FF6800}{ - } \left ( \color{#FF6800}{ c } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \left ( \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \left ( \color{#FF6800}{ b } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right )$
$ $ Sort the factors $ $
$\color{#FF6800}{ - } \left ( \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \left ( \color{#FF6800}{ b } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \left ( \color{#FF6800}{ c } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right )$
Solution search results
search-thumbnail-If the sum of two consecutive numbers is $45$ and one number is $X$ .This statement in the form of equation $1s:$ $\left(1$ Point) $\right)$ $○5x+1$ $1eft\left(x+1$ $r1gnt\right)=45s$ $○sx+1ef\left(x+2$ $r1gnt\right)=145s$ $sx+1x=45s$
7th-9th grade
Algebra
Check solution
search-thumbnail-$s|ef\left(-1n$ $\left($ }\right)^{50}\ $\right)$ \ | | is\ equal\ to\ $S$ $s1S$ $S-1S$ $s2S$ $s50s$
7th-9th grade
Other
Check solution
search-thumbnail-Given the set of ordered pairs $\left(\left(-7.0\right),\left(-6,5\right),\left(-5,-3\right),\left(-1,2\right)$ $\left(1,6\right),\left(2,-2\right)$ $\left(5,3\right)\left(7,-8\right)\right)$ Find f(7)fAleft(7\right) O a O b -8 6. $5$
7th-9th grade
Algebra
Check solution
search-thumbnail-The is the statement of the Mean Value Theorem from your $te\times tb00k$ $Tneoren$ $m4.5$ $Ne8n$ Value Theorem Let f be continuous over $leclose$ interval $\left(a.b\right)aod$ $i$ $eo$ $xd$ $csnlc$ $\left(ab\right)$ $mmd$ exists at least one point cE $\left(a.b\right)$ $si1dhtba$ $f^{'}\left(c\right)=\dfrac {f\left(b\right)-f\left(a\right)} {b-a}$ What is the geometric interpretation of the conclusion of the theorem? O The tangent line to the graph of \(f\left(x\right)\) at $l\left(c1\right)$ is parallel to the secant line connecting \(\left(a,f\left(a\right)\right)\) and \(\left(b,f\left(b\right)\right)\). O The tangent line to the graph of $\left(f\left(lef\left(x\left(right\right)$ at \(c\) is the secant line connecting \(\left(a,f\left(a\right)\right)\) $ana$ \(\left(b,f\left(b\right)\right)\). O The tangent line to the graph $of$ $\left(f\left(leF\left(x\left(right\right)\left(\right)at1\left(c1\right)is$ perpendicular to the secant line connecting \(\left(a,f\left(a\right)\right)\) and A(\left(b,f\left(b\right)\right)\). O The tangent line to the graph of $\left(fleH\left(x\right)nght\right)\right)\right)$ $at$ $\left(c\right)\right)ishoizonta|$ $Tnere$ is more than one tangent line to the graph $0no$ $\left(flcf\left(x\right)night\right)\left($ $at1\left(c1\right)$
Calculus
Check solution
search-thumbnail-What is the inverse of $g\left(x\right)=\sqrt{x-1} $ $Og\left(x\right)=\sqrt{x+1} $ $+1$ $g^{'}\left(x\right)=5-$ $y_{9}$ $g\sqrt{ef\left(x\left(nght\right)} =\left(f_{tac\left(x+1\right)0sq\pi \left(x\right)}$ $Og^{'}\left(x\right)=x^{2}+1$ $○g\left(x\right)=x^{2}-1$ « Previous Ne
Other
Check solution
search-thumbnail-What is the inverse of $g\left(x\right)=\sqrt{x-1} $ $Og\left(x\right)=\sqrt{x+1} $ $+1$ $g^{'}\left(x\right)=5-$ $y_{9}$ $g\sqrt{ef\left(x\left(nght\right)} =\left(f_{tac\left(x+1\right)0sq\pi \left(x\right)}$ $Og^{'}\left(x\right)=x^{2}+1$ $○g\left(x\right)=x^{2}-1$ « Previous Ne
Other
Check solution
Have you found the solution you wanted?
Try again
Try more features at QANDA!
Search by problem image
Ask 1:1 question to TOP class teachers
AI recommend problems and video lecture
apple logogoogle play logo