Calculator search results

Formula
Calculate the value
Answer
circle-check-icon
$\left( 1+ \sqrt{ 3 } \right) ^{ 2 } -2 \left( 1+ \sqrt{ 3 } \right) +1- \left( 1- \sqrt{ 3 } \right) ^{ 2 }$
$- 1 + 2 \sqrt{ 3 }$
Calculate the value
$\left ( \color{#FF6800}{ 1 } \color{#FF6800}{ + } \sqrt{ \color{#FF6800}{ 3 } } \right ) ^ { \color{#FF6800}{ 2 } } - 2 \left ( 1 + \sqrt{ 3 } \right ) + 1 - \left ( 1 - \sqrt{ 3 } \right ) ^ { 2 }$
$ $ Calculate power $ $
$\color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 3 } } + \color{#FF6800}{ 4 } - 2 \left ( 1 + \sqrt{ 3 } \right ) + 1 - \left ( 1 - \sqrt{ 3 } \right ) ^ { 2 }$
$2 \sqrt{ 3 } + 4 \color{#FF6800}{ - } \color{#FF6800}{ 2 } \left ( \color{#FF6800}{ 1 } \color{#FF6800}{ + } \sqrt{ \color{#FF6800}{ 3 } } \right ) + 1 - \left ( 1 - \sqrt{ 3 } \right ) ^ { 2 }$
$ $ Multiply each term in parentheses by $ - 2$
$2 \sqrt{ 3 } + 4 \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 3 } } + 1 - \left ( 1 - \sqrt{ 3 } \right ) ^ { 2 }$
$2 \sqrt{ 3 } + 4 - 2 - 2 \sqrt{ 3 } + 1 - \left ( \color{#FF6800}{ 1 } \color{#FF6800}{ - } \sqrt{ \color{#FF6800}{ 3 } } \right ) ^ { \color{#FF6800}{ 2 } }$
$ $ Calculate power $ $
$2 \sqrt{ 3 } + 4 - 2 - 2 \sqrt{ 3 } + 1 - \left ( \color{#FF6800}{ 4 } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 3 } } \right )$
$2 \sqrt{ 3 } + 4 - 2 - 2 \sqrt{ 3 } + 1 \color{#FF6800}{ - } \left ( \color{#FF6800}{ 4 } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 3 } } \right )$
$ $ Change the symbol of each term in parentheses when there is a (-) symbol in front of parentheses $ $
$2 \sqrt{ 3 } + 4 - 2 - 2 \sqrt{ 3 } + 1 \color{#FF6800}{ - } \color{#FF6800}{ 4 } + \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 3 } }$
$2 \sqrt{ 3 } \color{#FF6800}{ + } \color{#FF6800}{ 4 } - 2 - 2 \sqrt{ 3 } + 1 \color{#FF6800}{ - } \color{#FF6800}{ 4 } + 2 \sqrt{ 3 }$
$ $ Remove the two numbers if the values are the same and the signs are different $ $
$2 \sqrt{ 3 } - 2 - 2 \sqrt{ 3 } + 1 + 2 \sqrt{ 3 }$
$\color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 3 } } - \color{#FF6800}{ 2 } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 3 } } + 1 + 2 \sqrt{ 3 }$
$ $ Eliminate opponent number $ $
$- 2 + 1 + 2 \sqrt{ 3 }$
$\color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ + } \color{#FF6800}{ 1 } + 2 \sqrt{ 3 }$
$ $ Add $ - 2 $ and $ 1$
$\color{#FF6800}{ - } \color{#FF6800}{ 1 } + 2 \sqrt{ 3 }$
Solution search results
search-thumbnail-$s|ef\left(-1n$ $\left($ }\right)^{50}\ $\right)$ \ | | is\ equal\ to\ $S$ 
$s1S$ 
$S-1S$ 
$s2S$ 
$s50s$
7th-9th grade
Other
search-thumbnail-$8 \times $ 
$ = $ In $ \dfrac { E } { 8 } $ $ \left. \begin{array} { l } { \dfrac { 1 } { 3 } } \\ { \dfrac { 11 } { 3 } } \end{array} \right. $ $ \left. \begin{array} { l } { \dfrac { 1 } { 1 } } \\ { \dfrac { 1 } { 1 } } \end{array} \right. $ and $ \left. \begin{array} { l } { δ } \\ { 8 } \end{array} \right. $ 
Find the length of PR. $ \bar { I } $ 
$0$ 
$ \bar { u } $ 
$2$ $ = $ $ \| = $
7th-9th grade
Other
search-thumbnail-The rationalizing factor of \sqrt{23} is 
$°$ $Options^{°}$ $0$ 
A 24 
23 
C \sqrt{23} 
D None of these
7th-9th grade
Other
Have you found the solution you wanted?
Try again
Try more features at QANDA!
Search by problem image
Ask 1:1 question to TOP class teachers
AI recommend problems and video lecture
apple logogoogle play logo