Calculate the value

Arrange the rational expression

In the following problem $a,b,$ b,and c represent REAL NUMBERS. 
The derivative of $g\left(x\right)=log _{a}\left(bx\right)+cx^{2}is$ 
$○$ $g^{1}\left(x\right)=\right)dfrac\left(b\right)log _{-}a\left(bx\right)\right)\left(N1n$ $a\right)+2cx1\right)$ 
$○$ $\left(g\left(x\right)=\right)dtracb$ $loga\left(bx\right)+2c\times \right)Nln$ a}\) 
$○$ $g^{'}\left(x\right)=\left(dfraC\left(a\right)log _{-}a\left(bx\right)\right)\left(ln$ $\right)+2c\times 1\right)\right)$ 
$○$ $g^{1}\left(x\right)=\left(dfrac\left(b$ $log _{-}a\left(bx\right)\right)\left(ln$ $a1\right)$ 
$○$ $\left(\left(g^{1}\left(x\right)=b$ $log _{-}a\left(bx\right)+2cx1\right)$ 
$○$ $g\left(x\right)=\left(dfrac\left(b$ $log _{-}a\left(bx\right)\right)\left(1ln$ $a|+2c1\right)$ 

The is the statement of the Mean Value Theorem from your $te\times tb00k$ 
$Tneoren$ $m4.5$ $Ne8n$ Value Theorem 
Let f be continuous over $leclose$ interval $\left(a.b\right)aod$ $i$ $eo$ $xd$ $csnlc$ $\left(ab\right)$ $mmd$ 
exists at least one point cE $\left(a.b\right)$ $si1dhtba$ 
$f^{'}\left(c\right)=\dfrac {f\left(b\right)-f\left(a\right)} {b-a}$ 
What is the geometric interpretation of the conclusion of the theorem? 
O The tangent line to the graph of $f\left(x\right)$ at $l\left(c1\right)$ is parallel to the 
secant line connecting $\left(a,f\left(a\right)\right)$ and 
$\left(b,f\left(b\right)\right)$. 
O The tangent line to the graph of $\left(f\left(lef\left(x\left(right\right)$ at $c$ is the secant line 
connecting $\left(a,f\left(a\right)\right)$ $ana$ $\left(b,f\left(b\right)\right)$. 
O The tangent line to the graph $of$ $\left(f\left(leF\left(x\left(right\right)\left(\right)at1\left(c1\right)is$ perpendicular to the 
secant line connecting $\left(a,f\left(a\right)\right)$ and 
A(\left(b,f\left(b\right)\right)\). 
O The tangent line to the graph of $\left(fleH\left(x\right)nght\right)\right)\right)$ $at$ $\left(c\right)\right)ishoizonta|$ 
$Tnere$ is more than one tangent line to the graph $0no$ $\left(flcf\left(x\right)night\right)\left($ $at1\left(c1\right)$ 

$6\right)$ $\dfrac {3} {4}x-\dfrac {1} {2}=\dfrac {9} {8}x+\dfrac {3} {2}$ 
7) $6x-4\left(-2x+8\right)=10$ 
$8\right)$ $-2\left(4x-2\right)=-2\left(x-8\right)$ 
$9\right)$ $\left(2x-7\right)-\left(4x+8\right)=4\left(x+6\right)$ 
$10\right)$ $2\left(4x+3\right)=8x+1$ 

Solve for the variable in each of the following equation

$\left(int|imits$ $-0a1\left(1-\times n_{2}{\right)_{3}}^{n}$ 
$x^{A}3dx=7\right)$ 
$\left($ $frac\left(1\right)\left(40\right)\right)$ 
$\left($ $\left(troc\left(1\right)\left(35\right)\right)$ 
$\left(troc\left(1\right)\left(30\right)\right)$ 
$\left(tr0c\left(1\right)\left(25\right)\right)$ 

$11.$ Question $11$ 
Solve the $:$ $folloMlng'$ $0<θ<90^{°}$ 
$\left(1\right)$ $2sin^{2}θ=1\right)$ $\left(rac\left(3\right)\left(2\right)\right)$ 
$\left(11\right)$ $3tan^{2}θ+2=3$ 
$\left(111\right)cos^{2}θ$ $11rac\left(1\right)\left(4\right)\right)=$ 
$c\left(1\right)\left(4\right)\right)=11113c\left(1\right)\left(2\right)\right)$ 

Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8} 

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