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Formula
Calculate the value
Answer
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$\left( - \dfrac{ 9 }{ 10 } \right) \times \dfrac{ 2 }{ 3 } \div \left( - \dfrac{ 12 }{ 5 } \right)$
$\dfrac { 1 } { 4 }$
Calculate the value
$\color{#FF6800}{ - } \dfrac { 9 } { 10 } \times \color{#FF6800}{ \dfrac { 2 } { 3 } } \div \left ( \color{#FF6800}{ - } \dfrac { 12 } { 5 } \right )$
$ $ Since negative numbers are multiplied by an even number, remove the (-) sign $ $
$\dfrac { 9 } { 10 } \times \dfrac { 2 } { 3 } \div \dfrac { 12 } { 5 }$
$\dfrac { 9 } { 10 } \times \dfrac { 2 } { 3 } \color{#FF6800}{ \div } \color{#FF6800}{ \dfrac { 12 } { 5 } }$
$ $ Convert division to multiplication $ $
$\dfrac { 9 } { 10 } \times \dfrac { 2 } { 3 } \color{#FF6800}{ \times } \color{#FF6800}{ \dfrac { 5 } { 12 } }$
$\color{#FF6800}{ \dfrac { 9 } { 10 } } \color{#FF6800}{ \times } \color{#FF6800}{ \dfrac { 2 } { 3 } } \color{#FF6800}{ \times } \color{#FF6800}{ \dfrac { 5 } { 12 } }$
$ $ Calculate the product of rational numbers $ $
$\color{#FF6800}{ \dfrac { 1 } { 4 } }$
Solution search results
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numerator. 
$lg$ $\dfrac {5} {3}+\dfrac {2} {5}+\dfrac {3} {10}$ 
Here, $kCM\left(3$ $5$ $10\right)=30$ 
$\dfrac {5} {3}=\dfrac {5} {3}\times \dfrac {10} {10}=\dfrac {50} {30},\dfrac {2} {5}=\dfrac {2} {5}\times \dfrac {6} {6}=\dfrac {12} {30}$ 
and $\dfrac {3} {10}=\dfrac {3} {10}\times \dfrac {3} {3}=\dfrac {9} {30}$ 
$\dfrac {5} {3}+\dfrac {2} {5}+\dfrac {3} {10}$ $=\dfrac {50+12+9} {30}=\dfrac {71} {30}$ 
$1$
1st-6th grade
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