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Formula
Calculate the value
Answer
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$\left( - \dfrac{ 2 }{ 3 } \right) \times \left( - \dfrac{ 3 }{ 4 } + \dfrac{ 4 }{ 5 } \right) \times \dfrac{ 5 }{ 7 }$
$- \dfrac { 1 } { 42 }$
Calculate the value
$\color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 2 } { 3 } } \left ( \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 3 } { 4 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 4 } { 5 } } \right ) \color{#FF6800}{ \times } \color{#FF6800}{ \dfrac { 5 } { 7 } }$
$ $ Expand the expression to calculate the value $ $
$\color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 1 } { 42 } }$
Solution search results
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$3$ $\left(\dfrac {2} {3}\longdiv{}5\times \left(\dfrac {5} {7}\longdiv{}5$ is equal to : 
$\left(\dfrac {2} {3}\longdiv{}5\times \left(\dfrac {5} {7}\longdiv{}5$ 
$\left(a$ $\left(\dfrac {2} {3}\times \dfrac {5} {7}\right)=10$ $\left(b\right)$ $\left(\dfrac {2} {3}\times \dfrac {5} {7}\longdiv{}5$ 
$tc\right)$ $\left(\dfrac {2} {3}\times \dfrac {5} {7}\right)^{25}$ $1$ (d) $\right)$ $\left(\dfrac {2} {3}\times \dfrac {5} {7}\longdiv{}25$
7th-9th grade
Algebra
search-thumbnail-Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8}
7th-9th grade
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