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Formula
Find the sum or difference of the fractions
Answer
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$\left( + \dfrac{ 4 }{ 3 } \right) + \left( - \dfrac{ 1 }{ 2 } \right) + \left( + \dfrac{ 3 }{ 2 } \right) + \left( - \dfrac{ 5 }{ 3 } \right)$
$\dfrac { 2 } { 3 }$
Find the sum or difference of the fractions
$\dfrac { 4 } { \color{#FF6800}{ 3 } } - \dfrac { 1 } { \color{#FF6800}{ 2 } } + \dfrac { 3 } { \color{#FF6800}{ 2 } } - \dfrac { 5 } { \color{#FF6800}{ 3 } }$
$ $ The smallest common multiple in denominator is $ 6$
$\dfrac { 4 } { \color{#FF6800}{ 3 } } - \dfrac { 1 } { \color{#FF6800}{ 2 } } + \dfrac { 3 } { \color{#FF6800}{ 2 } } - \dfrac { 5 } { \color{#FF6800}{ 3 } }$
$\dfrac { 4 } { 3 } - \dfrac { 1 } { 2 } + \dfrac { 3 } { 2 } - \dfrac { 5 } { 3 }$
$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $
$\dfrac { 4 \times \color{#FF6800}{ 2 } } { 3 \times \color{#FF6800}{ 2 } } - \dfrac { 1 \times \color{#FF6800}{ 3 } } { 2 \times \color{#FF6800}{ 3 } } + \dfrac { 3 \times \color{#FF6800}{ 3 } } { 2 \times \color{#FF6800}{ 3 } } - \dfrac { 5 \times \color{#FF6800}{ 2 } } { 3 \times \color{#FF6800}{ 2 } }$
$\color{#FF6800}{ \dfrac { 4 \times 2 } { 3 \times 2 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 1 \times 3 } { 2 \times 3 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 3 \times 3 } { 2 \times 3 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 5 \times 2 } { 3 \times 2 } }$
$ $ Organize the expression $ $
$\color{#FF6800}{ \dfrac { 8 } { 6 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 3 } { 6 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 9 } { 6 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 10 } { 6 } }$
$\color{#FF6800}{ \dfrac { 8 } { 6 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 3 } { 6 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 9 } { 6 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 10 } { 6 } }$
$ $ Since the denominator is the same as $ 6 $ , combine the fractions into one $ $
$\color{#FF6800}{ \dfrac { 8 - 3 + 9 - 10 } { 6 } }$
$\dfrac { \color{#FF6800}{ 8 } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ + } \color{#FF6800}{ 9 } \color{#FF6800}{ - } \color{#FF6800}{ 10 } } { 6 }$
$ $ Calculate the sum or the difference $ $
$\dfrac { \color{#FF6800}{ 4 } } { 6 }$
$\color{#FF6800}{ \dfrac { 4 } { 6 } }$
$ $ Reduce the fraction to the lowest term $ $
$\color{#FF6800}{ \dfrac { 2 } { 3 } }$
Solution search results
search-thumbnail-$s|ef\left(-1n$ $\left($ }\right)^{50}\ $\right)$ \ | | is\ equal\ to\ $S$ 
$s1S$ 
$S-1S$ 
$s2S$ 
$s50s$
7th-9th grade
Other
search-thumbnail-
$2$ $5$ $8$ $\dfrac {5} {3}\times \dfrac {3} {2}=$ 
$3.$ $\dfrac {1} {3}x$ $-\times \dfrac {2} {3}$ $4$ $\dfrac {1} {3}\times \dfrac {3} {4}$ $\dfrac {4} {3}\times \dfrac {1} {2}$ $6$ $\dfrac {1} {2}\times \dfrac {5} {3}$ $\dfrac {4} {3}\times \dfrac {3} {4}$ $\dfrac {2} {3}\times \dfrac {7} {4}$ 9. $\dfrac {5} {3}$ $\dfrac {5} {4}$ $\dfrac {5} {4}\times 2=$ $2=$ 
$4$ $7$ $10$ $2x\dfrac {4} {3}=$ $2$ 
Check Your Understanding D $=$
1st-6th grade
Other
search-thumbnail-$11.$ Question $11$ 
Solve the $:$ $folloMlng'$ $0<θ<90^{°}$ 
$\left(1\right)$ $2sin^{2}θ=1\right)$ $\left(rac\left(3\right)\left(2\right)\right)$ 
$\left(11\right)$ $3tan^{2}θ+2=3$ 
$\left(111\right)cos^{2}θ$ $11rac\left(1\right)\left(4\right)\right)=$ 
$c\left(1\right)\left(4\right)\right)=11113c\left(1\right)\left(2\right)\right)$
10th-13th grade
Trigonometry
search-thumbnail-Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
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