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Formula
Find the sum of the fractions
Answer
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$\left( + \dfrac{ 2 }{ 3 } \right) + \left( + \dfrac{ 1 }{ 6 } \right)$
$\dfrac { 5 } { 6 }$
Find the sum of the fractions
$\dfrac { 2 } { \color{#FF6800}{ 3 } } + \dfrac { 1 } { \color{#FF6800}{ 6 } }$
$ $ The smallest common multiple in denominator is $ 6$
$\dfrac { 2 } { \color{#FF6800}{ 3 } } + \dfrac { 1 } { \color{#FF6800}{ 6 } }$
$\dfrac { 2 } { 3 } + \dfrac { 1 } { 6 }$
$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $
$\dfrac { 2 \times \color{#FF6800}{ 2 } } { 3 \times \color{#FF6800}{ 2 } } + \dfrac { 1 } { 6 }$
$\color{#FF6800}{ \dfrac { 2 \times 2 } { 3 \times 2 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 1 } { 6 } }$
$ $ Organize the expression $ $
$\color{#FF6800}{ \dfrac { 4 } { 6 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 1 } { 6 } }$
$\color{#FF6800}{ \dfrac { 4 } { 6 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 1 } { 6 } }$
$ $ Since the denominator is the same as $ 6 $ , combine the fractions into one $ $
$\color{#FF6800}{ \dfrac { 4 + 1 } { 6 } }$
$\dfrac { \color{#FF6800}{ 4 } \color{#FF6800}{ + } \color{#FF6800}{ 1 } } { 6 }$
$ $ Add $ 4 $ and $ 1$
$\dfrac { \color{#FF6800}{ 5 } } { 6 }$
Solution search results
search-thumbnail-$s|ef\left(-1n$ $\left($ }\right)^{50}\ $\right)$ \ | | is\ equal\ to\ $S$ 
$s1S$ 
$S-1S$ 
$s2S$ 
$s50s$
7th-9th grade
Other
search-thumbnail-$8 \times $ 
$ = $ In $ \dfrac { E } { 8 } $ $ \left. \begin{array} { l } { \dfrac { 1 } { 3 } } \\ { \dfrac { 11 } { 3 } } \end{array} \right. $ $ \left. \begin{array} { l } { \dfrac { 1 } { 1 } } \\ { \dfrac { 1 } { 1 } } \end{array} \right. $ and $ \left. \begin{array} { l } { δ } \\ { 8 } \end{array} \right. $ 
Find the length of PR. $ \bar { I } $ 
$0$ 
$ \bar { u } $ 
$2$ $ = $ $ \| = $
7th-9th grade
Other
search-thumbnail-Find the quotients. 
$1.8$ 
$. \varnothing 6 \sqrt { .10 } 8$ $ \left( 42 \right) $ 1.119.6 $ \sqrt { 9.68 } $ $ \left( 43 \right) $ $ \dfrac { .0312 } { 3 } $ 
06.10.8 
$ \left. \begin{array} { r } { 6 } \\ { 48 } \\ \hline \dfrac { 48 } { 0 } } \end{array} \right. $ $$
7th-9th grade
Algebra
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