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Find the difference
Answer
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$\left( \dfrac{ 4 }{ 7 } \right) + \left( - \dfrac{ 1 }{ 5 } \right)$
$\dfrac { 13 } { 35 }$
Find the difference
$\dfrac { 4 } { \color{#FF6800}{ 7 } } - \dfrac { 1 } { \color{#FF6800}{ 5 } }$
$ $ The smallest common multiple in denominator is $ 35$
$\dfrac { 4 } { \color{#FF6800}{ 7 } } - \dfrac { 1 } { \color{#FF6800}{ 5 } }$
$\dfrac { 4 } { 7 } - \dfrac { 1 } { 5 }$
$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $
$\dfrac { 4 \times \color{#FF6800}{ 5 } } { 7 \times \color{#FF6800}{ 5 } } - \dfrac { 1 \times \color{#FF6800}{ 7 } } { 5 \times \color{#FF6800}{ 7 } }$
$\color{#FF6800}{ \dfrac { 4 \times 5 } { 7 \times 5 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 1 \times 7 } { 5 \times 7 } }$
$ $ Organize the expression $ $
$\color{#FF6800}{ \dfrac { 20 } { 35 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 7 } { 35 } }$
$\color{#FF6800}{ \dfrac { 20 } { 35 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 7 } { 35 } }$
$ $ Since the denominator is the same as $ 35 $ , combine the fractions into one $ $
$\color{#FF6800}{ \dfrac { 20 - 7 } { 35 } }$
$\dfrac { \color{#FF6800}{ 20 } \color{#FF6800}{ - } \color{#FF6800}{ 7 } } { 35 }$
$ $ Subtract $ 7 $ from $ 20$
$\dfrac { \color{#FF6800}{ 13 } } { 35 }$
Solution search results
search-thumbnail-If the sum of two consecutive 
numbers is $45$ and one number is $X$ 
.This statement in the form of 
equation $1s:$ 
$\left(1$ Point) $\right)$ 
$○5x+1$ $1eft\left(x+1$ $r1gnt\right)=45s$ 
$○sx+1ef\left(x+2$ $r1gnt\right)=145s$ 
$sx+1x=45s$
7th-9th grade
Algebra
search-thumbnail-$s|ef\left(-1n$ $\left($ }\right)^{50}\ $\right)$ \ | | is\ equal\ to\ $S$ 
$s1S$ 
$S-1S$ 
$s2S$ 
$s50s$
7th-9th grade
Other
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