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Solve the equation
Answer
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Graph
$y = \dfrac { x } { 6 } + 5$
$y = \dfrac { 1 } { 3 } - x$
$x$Intercept
$\left ( - 30 , 0 \right )$
$y$Intercept
$\left ( 0 , 5 \right )$
$x$Intercept
$\left ( \dfrac { 1 } { 3 } , 0 \right )$
$y$Intercept
$\left ( 0 , \dfrac { 1 } { 3 } \right )$
$\dfrac{ x }{ 6 } +5 = \dfrac{ 1 }{ 3 } -x$
$x = - 4$
$ $ Solve a solution to $ x$
$\color{#FF6800}{ \dfrac { x } { 6 } } \color{#FF6800}{ + } \color{#FF6800}{ 5 } = \color{#FF6800}{ \dfrac { 1 } { 3 } } \color{#FF6800}{ - } \color{#FF6800}{ x }$
$ $ Multiply both sides by the least common multiple for the denominators to eliminate the fraction $ $
$\color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 30 } = \color{#FF6800}{ - } \color{#FF6800}{ 6 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 2 }$
$x + 30 = \color{#FF6800}{ - } \color{#FF6800}{ 6 } \color{#FF6800}{ x } + 2$
$ $ Move the variable to the left-hand side and change the symbol $ $
$x + 30 \color{#FF6800}{ + } \color{#FF6800}{ 6 } \color{#FF6800}{ x } = 2$
$x \color{#FF6800}{ + } \color{#FF6800}{ 30 } + 6 x = 2$
$ $ Move the constant to the right side and change the sign $ $
$x + 6 x = 2 \color{#FF6800}{ - } \color{#FF6800}{ 30 }$
$\color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 6 } \color{#FF6800}{ x } = 2 - 30$
$ $ Organize the expression $ $
$\color{#FF6800}{ 7 } \color{#FF6800}{ x } = 2 - 30$
$7 x = \color{#FF6800}{ 2 } \color{#FF6800}{ - } \color{#FF6800}{ 30 }$
$ $ Subtract $ 30 $ from $ 2$
$7 x = \color{#FF6800}{ - } \color{#FF6800}{ 28 }$
$\color{#FF6800}{ 7 } \color{#FF6800}{ x } = \color{#FF6800}{ - } \color{#FF6800}{ 28 }$
$ $ Divide both sides by the same number $ $
$\color{#FF6800}{ x } = \color{#FF6800}{ - } \color{#FF6800}{ 4 }$
$ $ 그래프 보기 $ $
Graph
Solution search results
search-thumbnail-$\dfrac {x} {6}+5=\dfrac {2} {3}y$
7th-9th grade
Algebra
search-thumbnail-Question $4$ 
If $x$ is $6$ what $|s$ 
$\dfrac {1} {3}x$ 
$1frac\left(1\right)\left(3\right)x$
1st-6th grade
Other
search-thumbnail-Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
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