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Find the difference
Answer
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$\dfrac { 27 } { 40 }$
Find the difference
$\dfrac { 7 } { \color{#FF6800}{ 8 } } - \dfrac { 1 } { \color{#FF6800}{ 5 } }$
$ $ The smallest common multiple in denominator is $ 40$
$\dfrac { 7 } { \color{#FF6800}{ 8 } } - \dfrac { 1 } { \color{#FF6800}{ 5 } }$
$\dfrac { 7 } { 8 } - \dfrac { 1 } { 5 }$
$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $
$\dfrac { 7 \times \color{#FF6800}{ 5 } } { 8 \times \color{#FF6800}{ 5 } } - \dfrac { 1 \times \color{#FF6800}{ 8 } } { 5 \times \color{#FF6800}{ 8 } }$
$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 7 } \color{#FF6800}{ \times } \color{#FF6800}{ 5 } } { \color{#FF6800}{ 8 } \color{#FF6800}{ \times } \color{#FF6800}{ 5 } } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 1 } \color{#FF6800}{ \times } \color{#FF6800}{ 8 } } { \color{#FF6800}{ 5 } \color{#FF6800}{ \times } \color{#FF6800}{ 8 } } }$
$ $ Organize the expression $ $
$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 35 } } { \color{#FF6800}{ 40 } } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 8 } } { \color{#FF6800}{ 40 } } }$
$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 35 } } { \color{#FF6800}{ 40 } } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 8 } } { \color{#FF6800}{ 40 } } }$
$ $ Since the denominator is the same as $ 40 $ , combine the fractions into one $ $
$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 35 } \color{#FF6800}{ - } \color{#FF6800}{ 8 } } { \color{#FF6800}{ 40 } } }$
$\dfrac { \color{#FF6800}{ 35 } \color{#FF6800}{ - } \color{#FF6800}{ 8 } } { 40 }$
$ $ Subtract $ 8 $ from $ 35$
$\dfrac { \color{#FF6800}{ 27 } } { 40 }$
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