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Formula
Find the sum of the fractions
Answer
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$\dfrac{ 7 }{ 8 } + \dfrac{ 5 }{ 6 }$
$\dfrac { 41 } { 24 }$
Find the sum of the fractions
$\dfrac { 7 } { \color{#FF6800}{ 8 } } + \dfrac { 5 } { \color{#FF6800}{ 6 } }$
$ $ The smallest common multiple in denominator is $ 24$
$\dfrac { 7 } { \color{#FF6800}{ 8 } } + \dfrac { 5 } { \color{#FF6800}{ 6 } }$
$\dfrac { 7 } { 8 } + \dfrac { 5 } { 6 }$
$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $
$\dfrac { 7 \times \color{#FF6800}{ 3 } } { 8 \times \color{#FF6800}{ 3 } } + \dfrac { 5 \times \color{#FF6800}{ 4 } } { 6 \times \color{#FF6800}{ 4 } }$
$\color{#FF6800}{ \dfrac { 7 \times 3 } { 8 \times 3 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 5 \times 4 } { 6 \times 4 } }$
$ $ Organize the expression $ $
$\color{#FF6800}{ \dfrac { 21 } { 24 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 20 } { 24 } }$
$\color{#FF6800}{ \dfrac { 21 } { 24 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 20 } { 24 } }$
$ $ Since the denominator is the same as $ 24 $ , combine the fractions into one $ $
$\color{#FF6800}{ \dfrac { 21 + 20 } { 24 } }$
$\dfrac { \color{#FF6800}{ 21 } \color{#FF6800}{ + } \color{#FF6800}{ 20 } } { 24 }$
$ $ Add $ 21 $ and $ 20$
$\dfrac { \color{#FF6800}{ 41 } } { 24 }$
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