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Find the sum of the fractions

Answer

$\dfrac { 3 } { 4 }$

Find the sum of the fractions

$\dfrac { 7 } { \color{#FF6800}{ 12 } } + \dfrac { 1 } { \color{#FF6800}{ 6 } }$

$ $ The smallest common multiple in denominator is $ 12$

$\dfrac { 7 } { \color{#FF6800}{ 12 } } + \dfrac { 1 } { \color{#FF6800}{ 6 } }$

$\dfrac { 7 } { 12 } + \dfrac { 1 } { 6 }$

$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $

$\dfrac { 7 } { 12 } + \dfrac { 1 \times \color{#FF6800}{ 2 } } { 6 \times \color{#FF6800}{ 2 } }$

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 7 } } { \color{#FF6800}{ 12 } } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 1 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } } { \color{#FF6800}{ 6 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } } }$

$ $ Organize the expression $ $

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 7 } } { \color{#FF6800}{ 12 } } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 2 } } { \color{#FF6800}{ 12 } } }$

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 7 } } { \color{#FF6800}{ 12 } } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 2 } } { \color{#FF6800}{ 12 } } }$

$ $ Since the denominator is the same as $ 12 $ , combine the fractions into one $ $

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 7 } \color{#FF6800}{ + } \color{#FF6800}{ 2 } } { \color{#FF6800}{ 12 } } }$

$\dfrac { \color{#FF6800}{ 7 } \color{#FF6800}{ + } \color{#FF6800}{ 2 } } { 12 }$

$ $ Add $ 7 $ and $ 2$

$\dfrac { \color{#FF6800}{ 9 } } { 12 }$

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 9 } } { \color{#FF6800}{ 12 } } }$

$ $ Reduce the fraction to the lowest term $ $

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 3 } } { \color{#FF6800}{ 4 } } }$

Solution search results

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