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Formula
Calculate the value
Answer
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$\dfrac{ 6 }{ 5 } \times \dfrac{ 6 }{ 5 }$
$\dfrac { 36 } { 25 }$
Calculate the value
$\color{#FF6800}{ \dfrac { 6 } { 5 } } \color{#FF6800}{ \times } \color{#FF6800}{ \dfrac { 6 } { 5 } }$
$ $ numerator multiply between numerator, and denominators multiply between denominators $ $
$\color{#FF6800}{ \dfrac { 6 \times 6 } { 5 \times 5 } }$
$\dfrac { \color{#FF6800}{ 6 } \color{#FF6800}{ \times } \color{#FF6800}{ 6 } } { 5 \times 5 }$
$ $ Multiply $ 6 $ and $ 6$
$\dfrac { \color{#FF6800}{ 36 } } { 5 \times 5 }$
$\dfrac { 36 } { \color{#FF6800}{ 5 } \color{#FF6800}{ \times } \color{#FF6800}{ 5 } }$
$ $ Multiply $ 5 $ and $ 5$
$\dfrac { 36 } { \color{#FF6800}{ 25 } }$
Solution search results
search-thumbnail-$\left(vi\right)$ $\left(\dfrac {6} {5}\right)^{5}\times \left(\dfrac {6} {5}\longdiv{}8$ $=\left(\dfrac {6} {5}\right)^{2x-3}$
1st-6th grade
Other
search-thumbnail-$\left(6^{-1}+\left(\dfrac {6} {5}\longdiv{}1\right)^{2}$
7th-9th grade
Calculus
search-thumbnail-$ \begin{cases} \dfrac {1} {5}x+\dfrac {1} {10}y=\dfrac {6} {5} \\ 3x+2y=17 \end{cases} $
10th-13th grade
Other
search-thumbnail-he problem. 
$5\right)$ The sum of two numbers is $-2$ Two times the first number equals $3$ times the second number. Find $25\right)$ 
the two numbers. 
A) $\dfrac {6} {5}$ and $\dfrac {4} {5}$ $B\right)$ $-\dfrac {6} {5}$ and $d-\dfrac {4} {5}$ C) $-2$ and $6$ D) $\right)$ $-6$ and $-4$
10th-13th grade
Other
search-thumbnail-$\left(11\right)$ $\left(\dfrac {2} {7}\longdiv{}5\times \left(\dfrac {2} {7}\right)^{m}$ $=\left(\dfrac {2} {7}\right)^{6}$ 
$\left(iy\right)$ $m^{3}=\left(\dfrac {6} {5}\longdiv{}3$ $\times \left(\dfrac {6} {5}\right)^{6}$
7th-9th grade
Calculus
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