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Formula
Find the difference
$\dfrac{ 6 }{ 128 } - \dfrac{ 2 }{ 64 } =$
$\dfrac { 1 } { 64 }$
Find the difference
$\color{#FF6800}{ \dfrac { 6 } { 128 } } - \dfrac { 2 } { 64 }$
 Reduce the fraction to the lowest term 
$\color{#FF6800}{ \dfrac { 3 } { 64 } } - \dfrac { 2 } { 64 }$
$\dfrac { 3 } { 64 } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 2 } { 64 } }$
 Reduce the fraction to the lowest term 
$\dfrac { 3 } { 64 } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 1 } { 32 } }$
$\dfrac { 3 } { \color{#FF6800}{ 64 } } - \dfrac { 1 } { \color{#FF6800}{ 32 } }$
 The smallest common multiple in denominator is $64$
$\dfrac { 3 } { \color{#FF6800}{ 64 } } - \dfrac { 1 } { \color{#FF6800}{ 32 } }$
$\dfrac { 3 } { 64 } - \dfrac { 1 } { 32 }$
 Multiply the denominator and the numerator so that the denominator is the smallest common multiple 
$\dfrac { 3 } { 64 } - \dfrac { 1 \times \color{#FF6800}{ 2 } } { 32 \times \color{#FF6800}{ 2 } }$
$\color{#FF6800}{ \dfrac { 3 } { 64 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 1 \times 2 } { 32 \times 2 } }$
 Organize the expression 
$\color{#FF6800}{ \dfrac { 3 } { 64 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 2 } { 64 } }$
$\color{#FF6800}{ \dfrac { 3 } { 64 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 2 } { 64 } }$
 Since the denominator is the same as $64$ , combine the fractions into one 
$\color{#FF6800}{ \dfrac { 3 - 2 } { 64 } }$
$\dfrac { \color{#FF6800}{ 3 } \color{#FF6800}{ - } \color{#FF6800}{ 2 } } { 64 }$
 Subtract $2$ from $3$
$\dfrac { \color{#FF6800}{ 1 } } { 64 }$
Solution search results
Algebra
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