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Calculate the value
Answer
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$\dfrac{ 6 }{ \sqrt{ 35 } } \times \sqrt{ 7 } + \dfrac{ \sqrt{ 90 } }{ 6 } \div \dfrac{ 5 \sqrt{ 2 } }{ 8 }$
$2 \sqrt{ 5 }$
Calculate the value
$\color{#FF6800}{ \dfrac { 6 } { \sqrt{ 35 } } } \sqrt{ \color{#FF6800}{ 7 } } + \dfrac { \sqrt{ 90 } } { 6 } \div \dfrac { 5 \sqrt{ 2 } } { 8 }$
$ $ Arrange the terms multiplied by fractions $ $
$\color{#FF6800}{ \dfrac { 6 \sqrt{ 7 } } { \sqrt{ 35 } } } + \dfrac { \sqrt{ 90 } } { 6 } \div \dfrac { 5 \sqrt{ 2 } } { 8 }$
$\color{#FF6800}{ \dfrac { 6 \sqrt{ 7 } } { \sqrt{ 35 } } } + \dfrac { \sqrt{ 90 } } { 6 } \div \dfrac { 5 \sqrt{ 2 } } { 8 }$
$ $ Calculate the expression $ $
$\color{#FF6800}{ \dfrac { 6 \sqrt{ 5 } } { 5 } } + \dfrac { \sqrt{ 90 } } { 6 } \div \dfrac { 5 \sqrt{ 2 } } { 8 }$
$\dfrac { 6 \sqrt{ 5 } } { 5 } + \color{#FF6800}{ \dfrac { \sqrt{ 90 } } { 6 } } \color{#FF6800}{ \div } \color{#FF6800}{ \dfrac { 5 \sqrt{ 2 } } { 8 } }$
$ $ Arrange the terms multiplied by fractions $ $
$\dfrac { 6 \sqrt{ 5 } } { 5 } + \color{#FF6800}{ \dfrac { \sqrt{ 90 } \times 8 } { 6 \left ( 5 \sqrt{ 2 } \right ) } }$
$\dfrac { 6 \sqrt{ 5 } } { 5 } + \dfrac { \sqrt{ \color{#FF6800}{ 90 } } \color{#FF6800}{ \times } \color{#FF6800}{ 8 } } { 6 \left ( 5 \sqrt{ 2 } \right ) }$
$ $ Simplify the expression $ $
$\dfrac { 6 \sqrt{ 5 } } { 5 } + \dfrac { \color{#FF6800}{ 24 } \sqrt{ \color{#FF6800}{ 10 } } } { 6 \left ( 5 \sqrt{ 2 } \right ) }$
$\dfrac { 6 \sqrt{ 5 } } { 5 } + \color{#FF6800}{ \dfrac { 24 \sqrt{ 10 } } { 6 \left ( 5 \sqrt{ 2 } \right ) } }$
$ $ Reduce the fraction $ $
$\dfrac { 6 \sqrt{ 5 } } { 5 } + \color{#FF6800}{ \dfrac { 4 \sqrt{ 10 } } { 5 \sqrt{ 2 } } }$
$\dfrac { 6 \sqrt{ 5 } } { 5 } + \color{#FF6800}{ \dfrac { 4 \sqrt{ 10 } } { 5 \sqrt{ 2 } } }$
$ $ Calculate the expression $ $
$\dfrac { 6 \sqrt{ 5 } } { 5 } + \color{#FF6800}{ \dfrac { 4 \sqrt{ 5 } } { 5 } }$
$\color{#FF6800}{ \dfrac { 6 \sqrt{ 5 } } { 5 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 4 \sqrt{ 5 } } { 5 } }$
$ $ Combine the fraction with the same denominator $ $
$\dfrac { \color{#FF6800}{ 6 } \sqrt{ \color{#FF6800}{ 5 } } \color{#FF6800}{ + } \color{#FF6800}{ 4 } \sqrt{ \color{#FF6800}{ 5 } } } { 5 }$
$\dfrac { \color{#FF6800}{ 6 } \sqrt{ \color{#FF6800}{ 5 } } \color{#FF6800}{ + } \color{#FF6800}{ 4 } \sqrt{ \color{#FF6800}{ 5 } } } { 5 }$
$ $ Calculate between similar terms $ $
$\dfrac { \color{#FF6800}{ 10 } \sqrt{ \color{#FF6800}{ 5 } } } { 5 }$
$\color{#FF6800}{ \dfrac { 10 \sqrt{ 5 } } { 5 } }$
$ $ Reduce the fraction $ $
$\color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 5 } }$
Solution search results
search-thumbnail-In the following problem $a,b,$ b,and c represent REAL NUMBERS. The derivative of $g\left(x\right)=log _{a}\left(bx\right)+cx^{2}is$ $○$ $g^{1}\left(x\right)=\right)dfrac\left(b\right)log _{-}a\left(bx\right)\right)\left(N1n$ $a\right)+2cx1\right)$ $○$ $\left(g\left(x\right)=\right)dtracb$ $loga\left(bx\right)+2c\times \right)Nln$ a}\) $○$ $g^{'}\left(x\right)=\left(dfraC\left(a\right)log _{-}a\left(bx\right)\right)\left(ln$ $\right)+2c\times 1\right)\right)$ $○$ $g^{1}\left(x\right)=\left(dfrac\left(b$ $log _{-}a\left(bx\right)\right)\left(ln$ $a1\right)$ $○$ $\left(\left(g^{1}\left(x\right)=b$ $log _{-}a\left(bx\right)+2cx1\right)$ $○$ $g\left(x\right)=\left(dfrac\left(b$ $log _{-}a\left(bx\right)\right)\left(1ln$ $a|+2c1\right)$
Calculus
Check solution
search-thumbnail-What is the inverse of $g\left(x\right)=\sqrt{x-1} $ $Og\left(x\right)=\sqrt{x+1} $ $+1$ $g^{'}\left(x\right)=5-$ $y_{9}$ $g\sqrt{ef\left(x\left(nght\right)} =\left(f_{tac\left(x+1\right)0sq\pi \left(x\right)}$ $Og^{'}\left(x\right)=x^{2}+1$ $○g\left(x\right)=x^{2}-1$ « Previous Ne
Other
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search-thumbnail-What is the inverse of $g\left(x\right)=\sqrt{x-1} $ $Og\left(x\right)=\sqrt{x+1} $ $+1$ $g^{'}\left(x\right)=5-$ $y_{9}$ $g\sqrt{ef\left(x\left(nght\right)} =\left(f_{tac\left(x+1\right)0sq\pi \left(x\right)}$ $Og^{'}\left(x\right)=x^{2}+1$ $○g\left(x\right)=x^{2}-1$ « Previous Ne
Other
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search-thumbnail-Which of the following rational numbers are equivalent? $0Ptionsy$ A \frac{5}{6}, \frac{30}{36} B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
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search-thumbnail-The rationalizing factor of \sqrt{23} is $°$ $Options^{°}$ $0$ A 24 23 C \sqrt{23} D None of these
7th-9th grade
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