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Calculate the value
Answer
$2 \sqrt{ 5 }$
Calculate the value
$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 6 } } { \sqrt{ \color{#FF6800}{ 35 } } } } \sqrt{ \color{#FF6800}{ 7 } } + \dfrac { \sqrt{ 90 } } { 6 } \div \dfrac { 5 \sqrt{ 2 } } { 8 }$
$ $ Arrange the terms multiplied by fractions $ $
$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 6 } \sqrt{ \color{#FF6800}{ 7 } } } { \sqrt{ \color{#FF6800}{ 35 } } } } + \dfrac { \sqrt{ 90 } } { 6 } \div \dfrac { 5 \sqrt{ 2 } } { 8 }$
$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 6 } \sqrt{ \color{#FF6800}{ 7 } } } { \sqrt{ \color{#FF6800}{ 35 } } } } + \dfrac { \sqrt{ 90 } } { 6 } \div \dfrac { 5 \sqrt{ 2 } } { 8 }$
$ $ Calculate the expression $ $
$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 6 } \sqrt{ \color{#FF6800}{ 5 } } } { \color{#FF6800}{ 5 } } } + \dfrac { \sqrt{ 90 } } { 6 } \div \dfrac { 5 \sqrt{ 2 } } { 8 }$
$\dfrac { 6 \sqrt{ 5 } } { 5 } + \color{#FF6800}{ \dfrac { \sqrt{ \color{#FF6800}{ 90 } } } { \color{#FF6800}{ 6 } } } \color{#FF6800}{ \div } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 5 } \sqrt{ \color{#FF6800}{ 2 } } } { \color{#FF6800}{ 8 } } }$
$ $ Arrange the terms multiplied by fractions $ $
$\dfrac { 6 \sqrt{ 5 } } { 5 } + \color{#FF6800}{ \dfrac { \sqrt{ \color{#FF6800}{ 90 } } \color{#FF6800}{ \times } \color{#FF6800}{ 8 } } { \color{#FF6800}{ 6 } \left ( \color{#FF6800}{ 5 } \sqrt{ \color{#FF6800}{ 2 } } \right ) } }$
$\dfrac { 6 \sqrt{ 5 } } { 5 } + \dfrac { \sqrt{ \color{#FF6800}{ 90 } } \color{#FF6800}{ \times } \color{#FF6800}{ 8 } } { 6 \left ( 5 \sqrt{ 2 } \right ) }$
$ $ Simplify the expression $ $
$\dfrac { 6 \sqrt{ 5 } } { 5 } + \dfrac { \color{#FF6800}{ 24 } \sqrt{ \color{#FF6800}{ 10 } } } { 6 \left ( 5 \sqrt{ 2 } \right ) }$
$\dfrac { 6 \sqrt{ 5 } } { 5 } + \color{#FF6800}{ \dfrac { \color{#FF6800}{ 24 } \sqrt{ \color{#FF6800}{ 10 } } } { \color{#FF6800}{ 6 } \left ( \color{#FF6800}{ 5 } \sqrt{ \color{#FF6800}{ 2 } } \right ) } }$
$ $ Reduce the fraction $ $
$\dfrac { 6 \sqrt{ 5 } } { 5 } + \color{#FF6800}{ \dfrac { \color{#FF6800}{ 4 } \sqrt{ \color{#FF6800}{ 10 } } } { \color{#FF6800}{ 5 } \sqrt{ \color{#FF6800}{ 2 } } } }$
$\dfrac { 6 \sqrt{ 5 } } { 5 } + \color{#FF6800}{ \dfrac { \color{#FF6800}{ 4 } \sqrt{ \color{#FF6800}{ 10 } } } { \color{#FF6800}{ 5 } \sqrt{ \color{#FF6800}{ 2 } } } }$
$ $ Calculate the expression $ $
$\dfrac { 6 \sqrt{ 5 } } { 5 } + \color{#FF6800}{ \dfrac { \color{#FF6800}{ 4 } \sqrt{ \color{#FF6800}{ 5 } } } { \color{#FF6800}{ 5 } } }$
$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 6 } \sqrt{ \color{#FF6800}{ 5 } } } { \color{#FF6800}{ 5 } } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 4 } \sqrt{ \color{#FF6800}{ 5 } } } { \color{#FF6800}{ 5 } } }$
$ $ Combine the fraction with the same denominator $ $
$\dfrac { \color{#FF6800}{ 6 } \sqrt{ \color{#FF6800}{ 5 } } \color{#FF6800}{ + } \color{#FF6800}{ 4 } \sqrt{ \color{#FF6800}{ 5 } } } { 5 }$
$\dfrac { \color{#FF6800}{ 6 } \sqrt{ \color{#FF6800}{ 5 } } \color{#FF6800}{ + } \color{#FF6800}{ 4 } \sqrt{ \color{#FF6800}{ 5 } } } { 5 }$
$ $ Calculate between similar terms $ $
$\dfrac { \color{#FF6800}{ 10 } \sqrt{ \color{#FF6800}{ 5 } } } { 5 }$
$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 10 } \sqrt{ \color{#FF6800}{ 5 } } } { \color{#FF6800}{ 5 } } }$
$ $ Reduce the fraction $ $
$\color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 5 } }$
Solution search results
Which of the following rational numbers are
equivalent?
$0Ptionsy$
A \frac{5}{6}, \frac{30}{36}
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $
D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
Search count: 5,909
Can you answer this?
$20$ $25$
$18$
$\left($
$\left(A\right)$ $A\right)2$
$21frac\left(5\right)\left(9\right)$ \)
$\left(B\right)$ $B\right)$ $1\left(211$
$\left(C\right)$ $1\left(21$ $21+rac\left(7\right)+9\right)$ \)
$\left(D\right)$ $1\left(2\right)$ 2\frac{8}{9}
$ac\left(8\right)\left(9\right)$ \) $9:18PM\sqrt{} $
1st-6th grade
Algebra
Search count: 1,480
The rationalizing factor of \sqrt{23} is
$°$ $Options^{°}$ $0$
A 24
23
C \sqrt{23}
D None of these
7th-9th grade
Other
Search count: 722
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