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Formula
Find the sum of the fractions
Answer
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$\dfrac{ 54 }{ 99 } + \dfrac{ 3 }{ 9 }$
$\dfrac { 29 } { 33 }$
Find the sum of the fractions
$\color{#FF6800}{ \dfrac { 54 } { 99 } } + \dfrac { 3 } { 9 }$
$ $ Do the reduction of the fraction format $ $
$\color{#FF6800}{ \dfrac { 6 } { 11 } } + \dfrac { 3 } { 9 }$
$\dfrac { 6 } { 11 } + \color{#FF6800}{ \dfrac { 3 } { 9 } }$
$ $ Do the reduction of the fraction format $ $
$\dfrac { 6 } { 11 } + \color{#FF6800}{ \dfrac { 1 } { 3 } }$
$\dfrac { 6 } { \color{#FF6800}{ 11 } } + \dfrac { 1 } { \color{#FF6800}{ 3 } }$
$ $ The smallest common multiple in denominator is $ 33$
$\dfrac { 6 } { \color{#FF6800}{ 11 } } + \dfrac { 1 } { \color{#FF6800}{ 3 } }$
$\dfrac { 6 } { 11 } + \dfrac { 1 } { 3 }$
$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $
$\dfrac { 6 \times \color{#FF6800}{ 3 } } { 11 \times \color{#FF6800}{ 3 } } + \dfrac { 1 \times \color{#FF6800}{ 11 } } { 3 \times \color{#FF6800}{ 11 } }$
$\color{#FF6800}{ \dfrac { 6 \times 3 } { 11 \times 3 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 1 \times 11 } { 3 \times 11 } }$
$ $ Organize the expression $ $
$\color{#FF6800}{ \dfrac { 18 } { 33 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 11 } { 33 } }$
$\color{#FF6800}{ \dfrac { 18 } { 33 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 11 } { 33 } }$
$ $ Since the denominator is the same as $ 33 $ , combine the fractions into one $ $
$\color{#FF6800}{ \dfrac { 18 + 11 } { 33 } }$
$\dfrac { \color{#FF6800}{ 18 } \color{#FF6800}{ + } \color{#FF6800}{ 11 } } { 33 }$
$ $ Add $ 18 $ and $ 11$
$\dfrac { \color{#FF6800}{ 29 } } { 33 }$
Solution search results
search-thumbnail-$yr\dfrac {6y} {11}=\dfrac {54} {99}$
7th-9th grade
Calculus
search-thumbnail-$yr\dfrac {6y} {11}=\dfrac {54} {99}$
7th-9th grade
Calculus
search-thumbnail-$.$ Find the value $0f.$ 
$2x$ $\tarc{y} $ 
to $\dfrac {1} {99}+\dfrac {2} {99}+\dfrac {3} {99}+$ $......+\dfrac {8} {99}+\dfrac {9} {99}+\dfrac {10} {99}$ 
$1A01e$ that $\dfrac {2} {99}=\dfrac {1} {99}\times 2\right)$
1st-6th grade
Calculus
search-thumbnail-$11.$ Question $11$ 
Solve the $:$ $folloMlng'$ $0<θ<90^{°}$ 
$\left(1\right)$ $2sin^{2}θ=1\right)$ $\left(rac\left(3\right)\left(2\right)\right)$ 
$\left(11\right)$ $3tan^{2}θ+2=3$ 
$\left(111\right)cos^{2}θ$ $11rac\left(1\right)\left(4\right)\right)=$ 
$c\left(1\right)\left(4\right)\right)=11113c\left(1\right)\left(2\right)\right)$
10th-13th grade
Trigonometry
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