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Find the difference
Answer
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$\dfrac{ 5 }{ 7 } - \dfrac{ 3 }{ 8 }$
$\dfrac { 19 } { 56 }$
Find the difference
$\dfrac { 5 } { \color{#FF6800}{ 7 } } - \dfrac { 3 } { \color{#FF6800}{ 8 } }$
$ $ The smallest common multiple in denominator is $ 56$
$\dfrac { 5 } { \color{#FF6800}{ 7 } } - \dfrac { 3 } { \color{#FF6800}{ 8 } }$
$\dfrac { 5 } { 7 } - \dfrac { 3 } { 8 }$
$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $
$\dfrac { 5 \times \color{#FF6800}{ 8 } } { 7 \times \color{#FF6800}{ 8 } } - \dfrac { 3 \times \color{#FF6800}{ 7 } } { 8 \times \color{#FF6800}{ 7 } }$
$\color{#FF6800}{ \dfrac { 5 \times 8 } { 7 \times 8 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 3 \times 7 } { 8 \times 7 } }$
$ $ Organize the expression $ $
$\color{#FF6800}{ \dfrac { 40 } { 56 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 21 } { 56 } }$
$\color{#FF6800}{ \dfrac { 40 } { 56 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 21 } { 56 } }$
$ $ Since the denominator is the same as $ 56 $ , combine the fractions into one $ $
$\color{#FF6800}{ \dfrac { 40 - 21 } { 56 } }$
$\dfrac { \color{#FF6800}{ 40 } \color{#FF6800}{ - } \color{#FF6800}{ 21 } } { 56 }$
$ $ Subtract $ 21 $ from $ 40$
$\dfrac { \color{#FF6800}{ 19 } } { 56 }$
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