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Formula
Find the sum of the fractions
Answer
$\dfrac{ 5 }{ 6 } + \dfrac{ 7 }{ 8 }$
$\dfrac { 41 } { 24 }$
Find the sum of the fractions
$\dfrac { 5 } { \color{#FF6800}{ 6 } } + \dfrac { 7 } { \color{#FF6800}{ 8 } }$
 The smallest common multiple in denominator is $24$
$\dfrac { 5 } { \color{#FF6800}{ 6 } } + \dfrac { 7 } { \color{#FF6800}{ 8 } }$
$\dfrac { 5 } { 6 } + \dfrac { 7 } { 8 }$
 Multiply the denominator and the numerator so that the denominator is the smallest common multiple 
$\dfrac { 5 \times \color{#FF6800}{ 4 } } { 6 \times \color{#FF6800}{ 4 } } + \dfrac { 7 \times \color{#FF6800}{ 3 } } { 8 \times \color{#FF6800}{ 3 } }$
$\color{#FF6800}{ \dfrac { 5 \times 4 } { 6 \times 4 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 7 \times 3 } { 8 \times 3 } }$
 Organize the expression 
$\color{#FF6800}{ \dfrac { 20 } { 24 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 21 } { 24 } }$
$\color{#FF6800}{ \dfrac { 20 } { 24 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 21 } { 24 } }$
 Since the denominator is the same as $24$ , combine the fractions into one 
$\color{#FF6800}{ \dfrac { 20 + 21 } { 24 } }$
$\dfrac { \color{#FF6800}{ 20 } \color{#FF6800}{ + } \color{#FF6800}{ 21 } } { 24 }$
 Add $20$ and $21$
$\dfrac { \color{#FF6800}{ 41 } } { 24 }$
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