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Find the difference

Answer

$\dfrac { 4 } { 21 }$

Find the difference

$\dfrac { 5 } { \color{#FF6800}{ 14 } } - \dfrac { 1 } { \color{#FF6800}{ 6 } }$

$ $ The smallest common multiple in denominator is $ 42$

$\dfrac { 5 } { \color{#FF6800}{ 14 } } - \dfrac { 1 } { \color{#FF6800}{ 6 } }$

$\dfrac { 5 } { 14 } - \dfrac { 1 } { 6 }$

$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $

$\dfrac { 5 \times \color{#FF6800}{ 3 } } { 14 \times \color{#FF6800}{ 3 } } - \dfrac { 1 \times \color{#FF6800}{ 7 } } { 6 \times \color{#FF6800}{ 7 } }$

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 5 } \color{#FF6800}{ \times } \color{#FF6800}{ 3 } } { \color{#FF6800}{ 14 } \color{#FF6800}{ \times } \color{#FF6800}{ 3 } } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 1 } \color{#FF6800}{ \times } \color{#FF6800}{ 7 } } { \color{#FF6800}{ 6 } \color{#FF6800}{ \times } \color{#FF6800}{ 7 } } }$

$ $ Organize the expression $ $

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 15 } } { \color{#FF6800}{ 42 } } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 7 } } { \color{#FF6800}{ 42 } } }$

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 15 } } { \color{#FF6800}{ 42 } } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 7 } } { \color{#FF6800}{ 42 } } }$

$ $ Since the denominator is the same as $ 42 $ , combine the fractions into one $ $

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 15 } \color{#FF6800}{ - } \color{#FF6800}{ 7 } } { \color{#FF6800}{ 42 } } }$

$\dfrac { \color{#FF6800}{ 15 } \color{#FF6800}{ - } \color{#FF6800}{ 7 } } { 42 }$

$ $ Subtract $ 7 $ from $ 15$

$\dfrac { \color{#FF6800}{ 8 } } { 42 }$

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 8 } } { \color{#FF6800}{ 42 } } }$

$ $ Reduce the fraction to the lowest term $ $

$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 4 } } { \color{#FF6800}{ 21 } } }$

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