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$\dfrac { 5 } { \color{#FF6800}{ 14 } } - \dfrac { 1 } { \color{#FF6800}{ 6 } }$

$ $ The smallest common multiple in denominator is $ 42$

$\dfrac { 5 } { \color{#FF6800}{ 14 } } - \dfrac { 1 } { \color{#FF6800}{ 6 } }$

$\dfrac { 5 } { 14 } - \dfrac { 1 } { 6 }$

$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $

$\dfrac { 5 \times \color{#FF6800}{ 3 } } { 14 \times \color{#FF6800}{ 3 } } - \dfrac { 1 \times \color{#FF6800}{ 7 } } { 6 \times \color{#FF6800}{ 7 } }$

$\color{#FF6800}{ \dfrac { 5 \times 3 } { 14 \times 3 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 1 \times 7 } { 6 \times 7 } }$

$ $ Organize the expression $ $

$\color{#FF6800}{ \dfrac { 15 } { 42 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 7 } { 42 } }$

$\color{#FF6800}{ \dfrac { 15 } { 42 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 7 } { 42 } }$

$ $ Since the denominator is the same as $ 42 $ , combine the fractions into one $ $

$\color{#FF6800}{ \dfrac { 15 - 7 } { 42 } }$

$\dfrac { \color{#FF6800}{ 15 } \color{#FF6800}{ - } \color{#FF6800}{ 7 } } { 42 }$

$ $ Subtract $ 7 $ from $ 15$

$\dfrac { \color{#FF6800}{ 8 } } { 42 }$

$\color{#FF6800}{ \dfrac { 8 } { 42 } }$

$ $ Reduce the fraction to the lowest term $ $

$\color{#FF6800}{ \dfrac { 4 } { 21 } }$