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Formula
Find the difference
Answer
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$\dfrac{ 5 }{ 14 } - \dfrac{ 1 }{ 6 }$
$\dfrac { 4 } { 21 }$
Find the difference
$\dfrac { 5 } { \color{#FF6800}{ 14 } } - \dfrac { 1 } { \color{#FF6800}{ 6 } }$
$ $ The smallest common multiple in denominator is $ 42$
$\dfrac { 5 } { \color{#FF6800}{ 14 } } - \dfrac { 1 } { \color{#FF6800}{ 6 } }$
$\dfrac { 5 } { 14 } - \dfrac { 1 } { 6 }$
$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $
$\dfrac { 5 \times \color{#FF6800}{ 3 } } { 14 \times \color{#FF6800}{ 3 } } - \dfrac { 1 \times \color{#FF6800}{ 7 } } { 6 \times \color{#FF6800}{ 7 } }$
$\color{#FF6800}{ \dfrac { 5 \times 3 } { 14 \times 3 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 1 \times 7 } { 6 \times 7 } }$
$ $ Organize the expression $ $
$\color{#FF6800}{ \dfrac { 15 } { 42 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 7 } { 42 } }$
$\color{#FF6800}{ \dfrac { 15 } { 42 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 7 } { 42 } }$
$ $ Since the denominator is the same as $ 42 $ , combine the fractions into one $ $
$\color{#FF6800}{ \dfrac { 15 - 7 } { 42 } }$
$\dfrac { \color{#FF6800}{ 15 } \color{#FF6800}{ - } \color{#FF6800}{ 7 } } { 42 }$
$ $ Subtract $ 7 $ from $ 15$
$\dfrac { \color{#FF6800}{ 8 } } { 42 }$
$\color{#FF6800}{ \dfrac { 8 } { 42 } }$
$ $ Reduce the fraction to the lowest term $ $
$\color{#FF6800}{ \dfrac { 4 } { 21 } }$
Solution search results
search-thumbnail-$11$ 
I examine if they are equal : 
$\left(i\right)$ $\left(\dfrac {5} {14}-\dfrac {-7} {9}\right)-\dfrac {3} {42},\dfrac {5} {14}-\left(\dfrac {-7} {9}-\dfrac {3} {42}\right)$ 
$.$ $\left(i11\right)$ $\dfrac {1} {6}+\dfrac {-2} {5}-\dfrac {-2} {15}$ $\left(iV\right)$ $1$ $-5$ $-+---$ 
(iv)
10th-13th grade
Other
search-thumbnail-Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
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