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Formula
Calculate the value
Answer
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$\dfrac{ 5 }{ 12 } \times 5$
$\dfrac { 25 } { 12 }$
Calculate the value
$\dfrac { 5 } { 12 } \color{#FF6800}{ \times } \color{#FF6800}{ 5 }$
$ $ Natural numbers can be expressed as fractions with a denominator of 1 $ $
$\dfrac { 5 } { 12 } \color{#FF6800}{ \times } \color{#FF6800}{ \dfrac { 5 } { 1 } }$
$\color{#FF6800}{ \dfrac { 5 } { 12 } } \color{#FF6800}{ \times } \color{#FF6800}{ \dfrac { 5 } { 1 } }$
$ $ numerator multiply between numerator, and denominators multiply between denominators $ $
$\color{#FF6800}{ \dfrac { 5 \times 5 } { 12 \times 1 } }$
$\dfrac { \color{#FF6800}{ 5 } \color{#FF6800}{ \times } \color{#FF6800}{ 5 } } { 12 \times 1 }$
$ $ Multiply $ 5 $ and $ 5$
$\dfrac { \color{#FF6800}{ 25 } } { 12 \times 1 }$
$\dfrac { 25 } { 12 \color{#FF6800}{ \times } \color{#FF6800}{ 1 } }$
$ $ Multiplying any number by 1 does not change the value $ $
$\dfrac { 25 } { \color{#FF6800}{ 12 } }$
Solution search results
search-thumbnail-If $\left(\dfrac {5} {12}\right)^{3}$ $\times \left(\dfrac {5} {12}\longdiv{}6x$ $=\left(\dfrac {5} {12}\longdiv{}12$ then x $x=7$
7th-9th grade
Algebra
search-thumbnail-
(a) $32$ (b) $3^{2}$ $=$ $3$ 
10 $x$ $\dfrac {5} {12}\longdiv{}4.\left(\dfrac {5} {12}\right)^{x}$ $=\left(\dfrac {5} {12}\right)^{3}$ then $x==$ 
$a=1$ $b^{\right)}$ $0$ $a$ 
$3^{2}$
10th-13th grade
Other
search-thumbnail-Can you answer this? 
$20$ $25$ 

$18$ 

$\left($ 
$\left(A\right)$ $A\right)2$ 
$21frac\left(5\right)\left(9\right)$ \) 
$\left(B\right)$ $B\right)$ $1\left(211$ 
$\left(C\right)$ $1\left(21$ $21+rac\left(7\right)+9\right)$ \) 
$\left(D\right)$ $1\left(2\right)$ 2\frac{8}{9} 
$ac\left(8\right)\left(9\right)$ \) $9:18PM\sqrt{} $
1st-6th grade
Algebra
search-thumbnail-$4-$ $\left(\dfrac {5} {12}\longdiv{}y\times \left(\dfrac {5} {12}\right)^{3x}=\dfrac {5\right)} {\left(12}^{5}$ then $2=2$
7th-9th grade
Other
search-thumbnail-Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
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