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Formula

Calculate the value

Answer

$\dfrac{ 4 }{ 3 } \times 6- \left( \dfrac{ 1 }{ 2 } - \left( - \dfrac{ 3 }{ 2 } \right) \times \dfrac{ 7 }{ 2 } \right) -5$

$- \dfrac { 11 } { 4 }$

Calculate the value

$\color{#FF6800}{ \dfrac { 4 } { 3 } } \color{#FF6800}{ \times } \color{#FF6800}{ 6 } - \left ( \dfrac { 1 } { 2 } - \left ( - \dfrac { 3 } { 2 } \right ) \times \dfrac { 7 } { 2 } \right ) - 5$

$ $ Calculate the product of rational numbers $ $

$\color{#FF6800}{ 8 } - \left ( \dfrac { 1 } { 2 } - \left ( - \dfrac { 3 } { 2 } \right ) \times \dfrac { 7 } { 2 } \right ) - 5$

$8 - \left ( \dfrac { 1 } { 2 } \color{#FF6800}{ - } \left ( \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 3 } { 2 } } \right ) \color{#FF6800}{ \times } \color{#FF6800}{ \dfrac { 7 } { 2 } } \right ) - 5$

$ $ Arrange the terms multiplied by fractions $ $

$8 - \left ( \dfrac { 1 } { 2 } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { - \dfrac { 3 } { 2 } \times 7 } { 2 } } \right ) - 5$

$8 - \left ( \color{#FF6800}{ \dfrac { 1 } { 2 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { - \dfrac { 3 } { 2 } \times 7 } { 2 } } \right ) - 5$

$ $ Combine the fraction with the same denominator $ $

$8 - \dfrac { \color{#FF6800}{ 1 } \color{#FF6800}{ - } \left ( \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 3 } { 2 } } \color{#FF6800}{ \times } \color{#FF6800}{ 7 } \right ) } { 2 } - 5$

$8 - \dfrac { 1 \color{#FF6800}{ - } \left ( \color{#FF6800}{ - } \dfrac { 3 } { 2 } \times 7 \right ) } { 2 } - 5$

$ $ Simplify Minus $ $

$8 - \dfrac { 1 + \dfrac { 3 } { 2 } \times 7 } { 2 } - 5$

$8 - \dfrac { 1 + \color{#FF6800}{ \dfrac { 3 } { 2 } } \color{#FF6800}{ \times } \color{#FF6800}{ 7 } } { 2 } - 5$

$ $ Calculate the product of rational numbers $ $

$8 - \dfrac { 1 + \color{#FF6800}{ \dfrac { 21 } { 2 } } } { 2 } - 5$

$8 - \dfrac { \color{#FF6800}{ 1 } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 21 } { 2 } } } { 2 } - 5$

$ $ Add two numbers $ 1 $ and $ \dfrac { 21 } { 2 }$

$8 - \dfrac { \color{#FF6800}{ \dfrac { 23 } { 2 } } } { 2 } - 5$

$8 \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { \dfrac { 23 } { 2 } } { 2 } } - 5$

$ $ Calculate the complex fraction $ $

$8 \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 23 } { 2 \times 2 } } - 5$

$8 - \dfrac { 23 } { \color{#FF6800}{ 2 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } } - 5$

$ $ Multiply $ 2 $ and $ 2$

$8 - \dfrac { 23 } { \color{#FF6800}{ 4 } } - 5$

$\color{#FF6800}{ 8 } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 23 } { 4 } } \color{#FF6800}{ - } \color{#FF6800}{ 5 }$

$ $ Calculate the sum or the difference $ $

$\color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 11 } { 4 } }$

Solution search results

search-thumbnail-$The\ reciprocal\\ 0+11) \left(\frac{2}

$8$ $\left(1$ Point) $1\right)$ The\ reciprocal\\ $0+11\right)$ \left(\frac{2} $c\left(2\right)$ {5}\right)^0\ $\right)$ \ $1111s\right)$ $S$ $S1S$ $s3S$ $S4S$ $s2S$

7th-9th grade

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search-thumbnail-Which of the following rational numbers are

Which of the following rational numbers are equivalent? $0Ptionsy$ A \frac{5}{6}, \frac{30}{36} B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ D \frac{1}{2},\frac{3}{8}

7th-9th grade

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search-thumbnail-Can you answer this?

Can you answer this? $20$ $25$ $18$ $\left($ $\left(A\right)$ $A\right)2$ $21frac\left(5\right)\left(9\right)$ \) $\left(B\right)$ $B\right)$ $1\left(211$ $\left(C\right)$ $1\left(21$ $21+rac\left(7\right)+9\right)$ \) $\left(D\right)$ $1\left(2\right)$ 2\frac{8}{9} $ac\left(8\right)\left(9\right)$ \) $9:18PM\sqrt{} $

1st-6th grade

Algebra

Search count: 1,480

search-thumbnail-Theis the statement of the Mean Value Theorem from your te\timestb00k

The is the statement of the Mean Value Theorem from your $te\times tb00k$ $Tneoren$ $m4.5$ $Ne8n$ Value Theorem Let f be continuous over $leclose$ interval $\left(a.b\right)aod$ $i$ $eo$ $xd$ $csnlc$ $\left(ab\right)$ $mmd$ exists at least one point cE $\left(a.b\right)$ $si1dhtba$ $f^{'}\left(c\right)=\dfrac {f\left(b\right)-f\left(a\right)} {b-a}$ What is the geometric interpretation of the conclusion of the theorem? O The tangent line to the graph of \(f\left(x\right)\) at $l\left(c1\right)$ is parallel to the secant line connecting \(\left(a,f\left(a\right)\right)\) and \(\left(b,f\left(b\right)\right)\). O The tangent line to the graph of $\left(f\left(lef\left(x\left(right\right)$ at \(c\) is the secant line connecting \(\left(a,f\left(a\right)\right)\) $ana$ \(\left(b,f\left(b\right)\right)\). O The tangent line to the graph $of$ $\left(f\left(leF\left(x\left(right\right)\left(\right)at1\left(c1\right)is$ perpendicular to the secant line connecting \(\left(a,f\left(a\right)\right)\) and A(\left(b,f\left(b\right)\right)\). O The tangent line to the graph of $\left(fleH\left(x\right)nght\right)\right)\right)$ $at$ $\left(c\right)\right)ishoizonta|$ $Tnere$ is more than one tangent line to the graph $0no$ $\left(flcf\left(x\right)night\right)\left($ $at1\left(c1\right)$

Calculus

Search count: 3,278

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