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Formula
Find the difference
Answer
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$\dfrac{ 3 }{ 5 } - \dfrac{ 4 }{ 7 }$
$\dfrac { 1 } { 35 }$
Find the difference
$\dfrac { 3 } { \color{#FF6800}{ 5 } } - \dfrac { 4 } { \color{#FF6800}{ 7 } }$
$ $ The smallest common multiple in denominator is $ 35$
$\dfrac { 3 } { \color{#FF6800}{ 5 } } - \dfrac { 4 } { \color{#FF6800}{ 7 } }$
$\dfrac { 3 } { 5 } - \dfrac { 4 } { 7 }$
$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $
$\dfrac { 3 \times \color{#FF6800}{ 7 } } { 5 \times \color{#FF6800}{ 7 } } - \dfrac { 4 \times \color{#FF6800}{ 5 } } { 7 \times \color{#FF6800}{ 5 } }$
$\color{#FF6800}{ \dfrac { 3 \times 7 } { 5 \times 7 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 4 \times 5 } { 7 \times 5 } }$
$ $ Organize the expression $ $
$\color{#FF6800}{ \dfrac { 21 } { 35 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 20 } { 35 } }$
$\color{#FF6800}{ \dfrac { 21 } { 35 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 20 } { 35 } }$
$ $ Since the denominator is the same as $ 35 $ , combine the fractions into one $ $
$\color{#FF6800}{ \dfrac { 21 - 20 } { 35 } }$
$\dfrac { \color{#FF6800}{ 21 } \color{#FF6800}{ - } \color{#FF6800}{ 20 } } { 35 }$
$ $ Subtract $ 20 $ from $ 21$
$\dfrac { \color{#FF6800}{ 1 } } { 35 }$
Solution search results
search-thumbnail-$-$ $-$ $-$ $+\left(\dfrac {3} {8}+\dfrac {7} {6}\right)=\left(\dfrac {5} {4}+\dfrac {3} {8}\right)+\dfrac {7} {6}$ 
T HHTT a $7$ 
$-$ $-\dfrac {3} {5}+\left(\dfrac {2} {3}+\dfrac {4} {7}\right)=\left(\dfrac {3} {5}+\dfrac {2} {3}\right)+\dfrac {4} {7}$
10th-13th grade
Other
search-thumbnail-$11.$ Question $11$ 
Solve the $:$ $folloMlng'$ $0<θ<90^{°}$ 
$\left(1\right)$ $2sin^{2}θ=1\right)$ $\left(rac\left(3\right)\left(2\right)\right)$ 
$\left(11\right)$ $3tan^{2}θ+2=3$ 
$\left(111\right)cos^{2}θ$ $11rac\left(1\right)\left(4\right)\right)=$ 
$c\left(1\right)\left(4\right)\right)=11113c\left(1\right)\left(2\right)\right)$
10th-13th grade
Trigonometry
search-thumbnail-Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
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