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Formula
Find the difference
$\dfrac{ 3 }{ 4 } + \left( - \dfrac{ 2 }{ 3 } \right)$
$\dfrac { 1 } { 12 }$
Find the difference
$\dfrac { 3 } { \color{#FF6800}{ 4 } } - \dfrac { 2 } { \color{#FF6800}{ 3 } }$
 The smallest common multiple in denominator is $12$
$\dfrac { 3 } { \color{#FF6800}{ 4 } } - \dfrac { 2 } { \color{#FF6800}{ 3 } }$
$\dfrac { 3 } { 4 } - \dfrac { 2 } { 3 }$
 Multiply the denominator and the numerator so that the denominator is the smallest common multiple 
$\dfrac { 3 \times \color{#FF6800}{ 3 } } { 4 \times \color{#FF6800}{ 3 } } - \dfrac { 2 \times \color{#FF6800}{ 4 } } { 3 \times \color{#FF6800}{ 4 } }$
$\color{#FF6800}{ \dfrac { 3 \times 3 } { 4 \times 3 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 2 \times 4 } { 3 \times 4 } }$
 Organize the expression 
$\color{#FF6800}{ \dfrac { 9 } { 12 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 8 } { 12 } }$
$\color{#FF6800}{ \dfrac { 9 } { 12 } } \color{#FF6800}{ - } \color{#FF6800}{ \dfrac { 8 } { 12 } }$
 Since the denominator is the same as $12$ , combine the fractions into one 
$\color{#FF6800}{ \dfrac { 9 - 8 } { 12 } }$
$\dfrac { \color{#FF6800}{ 9 } \color{#FF6800}{ - } \color{#FF6800}{ 8 } } { 12 }$
 Subtract $8$ from $9$
$\dfrac { \color{#FF6800}{ 1 } } { 12 }$
Solution search results