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Formula
Find the sum of the fractions
Answer
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$\dfrac{ 2 }{ 3 } + \dfrac{ 4 }{ 7 }$
$\dfrac { 26 } { 21 }$
Find the sum of the fractions
$\dfrac { 2 } { \color{#FF6800}{ 3 } } + \dfrac { 4 } { \color{#FF6800}{ 7 } }$
$ $ The smallest common multiple in denominator is $ 21$
$\dfrac { 2 } { \color{#FF6800}{ 3 } } + \dfrac { 4 } { \color{#FF6800}{ 7 } }$
$\dfrac { 2 } { 3 } + \dfrac { 4 } { 7 }$
$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $
$\dfrac { 2 \times \color{#FF6800}{ 7 } } { 3 \times \color{#FF6800}{ 7 } } + \dfrac { 4 \times \color{#FF6800}{ 3 } } { 7 \times \color{#FF6800}{ 3 } }$
$\color{#FF6800}{ \dfrac { 2 \times 7 } { 3 \times 7 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 4 \times 3 } { 7 \times 3 } }$
$ $ Organize the expression $ $
$\color{#FF6800}{ \dfrac { 14 } { 21 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 12 } { 21 } }$
$\color{#FF6800}{ \dfrac { 14 } { 21 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 12 } { 21 } }$
$ $ Since the denominator is the same as $ 21 $ , combine the fractions into one $ $
$\color{#FF6800}{ \dfrac { 14 + 12 } { 21 } }$
$\dfrac { \color{#FF6800}{ 14 } \color{#FF6800}{ + } \color{#FF6800}{ 12 } } { 21 }$
$ $ Add $ 14 $ and $ 12$
$\dfrac { \color{#FF6800}{ 26 } } { 21 }$
Solution search results
search-thumbnail-Compute and express the result as a mixed fraction? 
$①$ $2+\dfrac {3} {4}$ $-$ $\left(n\right)$ $\dfrac {7} {9}+\dfrac {1} {3}$ $1-\dfrac {4} {7}$ 
$-$ $\left(y\right)$ $2\dfrac {2} {3}+\dfrac {1} {2}$ $\left(y\right)$ $\dfrac {5} {8}-\dfrac {1} {6}$ $\left(n\right)$ $2\dfrac {2} {3}+3\dfrac {1} {2}$
7th-9th grade
Other
search-thumbnail-Exercise $=1$ 
Compute and express the result as a mixed fraction? 
$\right)$ $2+\dfrac {3} {4}$ $\left(0\right)$ $\dfrac {7} {9}+\dfrac {1} {3}$ (m) $1-\dfrac {4} {7}$ 
$-$ $\left(w\right)$ $2\dfrac {2} {3}+\dfrac {1} {2}$ $\left(y\right)$ $\dfrac {5} {8}-\dfrac {1} {6}$ $\left(m\right)$ $2\dfrac {2} {3}+3\dfrac {1} {2}$
7th-9th grade
Other
search-thumbnail-$2$ Show $that:$ 
$\dfrac {4} {7}\left(\dfrac {2} {3}+\dfrac {3} {4}\right)=\left(\dfrac {4} {7}\times \dfrac {2} {3}\right)+\left(\dfrac {4} {7}\times \dfrac {3} {4}\right)$
7th-9th grade
Other
search-thumbnail-Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
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