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Formula
Find the sum of the fractions
Answer
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$\dfrac{ 18 }{ 7 } + \dfrac{ 45 }{ 14 }$
$\dfrac { 81 } { 14 }$
Find the sum of the fractions
$\dfrac { 18 } { \color{#FF6800}{ 7 } } + \dfrac { 45 } { \color{#FF6800}{ 14 } }$
$ $ The smallest common multiple in denominator is $ 14$
$\dfrac { 18 } { \color{#FF6800}{ 7 } } + \dfrac { 45 } { \color{#FF6800}{ 14 } }$
$\dfrac { 18 } { 7 } + \dfrac { 45 } { 14 }$
$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $
$\dfrac { 18 \times \color{#FF6800}{ 2 } } { 7 \times \color{#FF6800}{ 2 } } + \dfrac { 45 } { 14 }$
$\color{#FF6800}{ \dfrac { 18 \times 2 } { 7 \times 2 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 45 } { 14 } }$
$ $ Organize the expression $ $
$\color{#FF6800}{ \dfrac { 36 } { 14 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 45 } { 14 } }$
$\color{#FF6800}{ \dfrac { 36 } { 14 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 45 } { 14 } }$
$ $ Since the denominator is the same as $ 14 $ , combine the fractions into one $ $
$\color{#FF6800}{ \dfrac { 36 + 45 } { 14 } }$
$\dfrac { \color{#FF6800}{ 36 } \color{#FF6800}{ + } \color{#FF6800}{ 45 } } { 14 }$
$ $ Add $ 36 $ and $ 45$
$\dfrac { \color{#FF6800}{ 81 } } { 14 }$
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