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Formula
Find the sum of the fractions
Answer
$\dfrac{ 11 }{ 24 } + \dfrac{ 1 }{ 6 }$
$\dfrac { 5 } { 8 }$
Find the sum of the fractions
$\dfrac { 11 } { \color{#FF6800}{ 24 } } + \dfrac { 1 } { \color{#FF6800}{ 6 } }$
 The smallest common multiple in denominator is $24$
$\dfrac { 11 } { \color{#FF6800}{ 24 } } + \dfrac { 1 } { \color{#FF6800}{ 6 } }$
$\dfrac { 11 } { 24 } + \dfrac { 1 } { 6 }$
 Multiply the denominator and the numerator so that the denominator is the smallest common multiple 
$\dfrac { 11 } { 24 } + \dfrac { 1 \times \color{#FF6800}{ 4 } } { 6 \times \color{#FF6800}{ 4 } }$
$\color{#FF6800}{ \dfrac { 11 } { 24 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 1 \times 4 } { 6 \times 4 } }$
 Organize the expression 
$\color{#FF6800}{ \dfrac { 11 } { 24 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 4 } { 24 } }$
$\color{#FF6800}{ \dfrac { 11 } { 24 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 4 } { 24 } }$
 Since the denominator is the same as $24$ , combine the fractions into one 
$\color{#FF6800}{ \dfrac { 11 + 4 } { 24 } }$
$\dfrac { \color{#FF6800}{ 11 } \color{#FF6800}{ + } \color{#FF6800}{ 4 } } { 24 }$
 Add $11$ and $4$
$\dfrac { \color{#FF6800}{ 15 } } { 24 }$
$\color{#FF6800}{ \dfrac { 15 } { 24 } }$
 Reduce the fraction to the lowest term 
$\color{#FF6800}{ \dfrac { 5 } { 8 } }$
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