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Formula
Reduce the fraction to the lowest term
Answer
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Convert a fraction to %
Answer
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Convert fractions to decimals
Answer
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$\dfrac{ 10 }{ 200 }$
$\dfrac { 1 } { 20 }$
Reduce the fraction to the lowest term
$\color{#FF6800}{ \dfrac { 10 } { 200 } }$
$ $ Divide the denominator by the greatest common factor $ 10$
$\color{#FF6800}{ \dfrac { 10 \div 10 } { 200 \div 10 } }$
$\dfrac { \color{#FF6800}{ 10 } \color{#FF6800}{ \div } \color{#FF6800}{ 10 } } { 200 \div 10 }$
$ $ Divide $ 10 $ by $ 10$
$\dfrac { \color{#FF6800}{ 1 } } { 200 \div 10 }$
$\dfrac { 1 } { \color{#FF6800}{ 200 } \color{#FF6800}{ \div } \color{#FF6800}{ 10 } }$
$ $ Divide $ 200 $ by $ 10$
$\dfrac { 1 } { \color{#FF6800}{ 20 } }$
$5.0 \%$
Convert a fraction to %
$\color{#FF6800}{ \dfrac { 10 } { 200 } }$
$ $ Reduce the fraction to the lowest term $ $
$\color{#FF6800}{ \dfrac { 1 } { 20 } }$
$\color{#FF6800}{ \dfrac { 1 } { 20 } }$
$ $ Convert fractions to decimals $ $
$\color{#FF6800}{ 0.05 }$
$\color{#FF6800}{ 0.05 }$
$ $ Multiply by 100 to be presented as % $ $
$0.05 \times \color{#FF6800}{ 100 } = \color{#FF6800}{ 5.0 }$
$0.05 \times \color{#FF6800}{ 100 } = \color{#FF6800}{ 5.0 }$
$ $ Attach % $ $
$\color{#FF6800}{ 5.0 \% }$
$0.05$
Convert fractions to decimals
$\color{#FF6800}{ \dfrac { 10 } { 200 } }$
$ $ Convert fractions to decimals $ $
$\color{#FF6800}{ 0.05 }$
Solution search results
search-thumbnail-$A$ roll $0$ $40$ quarters weigh $8$ ounces. Which proportion can be used to find the weight, in ounces, of the $200$ quarters? 
$A$ $\dfrac {40} {8}=\dfrac {200} {x}$ 
$B$ $\dfrac {40} {ta}=\dfrac {8} {200}$ 
$C$ $\dfrac {40} {200}=\dfrac {tw} {8}$ 
$D$ $\dfrac {40} {8+y}=\dfrac {10} {200}$
7th-9th grade
Other
search-thumbnail-$A$ roll $0$ $40$ quarters weigh $8$ ounces. Which proportion can be used to find the weight, in ounces, of the $200$ quarters? 
$A$ $\dfrac {40} {8}=\dfrac {200} {x}$ 
$B$ $\dfrac {40} {ta}=\dfrac {8} {200}$ 
$C$ $\dfrac {40} {200}=\dfrac {tw} {8}$ 
$D$ $\dfrac {40} {8+y}=\dfrac {10} {200}$
7th-9th grade
Other
search-thumbnail-$11.$ Question $11$ 
Solve the $:$ $folloMlng'$ $0<θ<90^{°}$ 
$\left(1\right)$ $2sin^{2}θ=1\right)$ $\left(rac\left(3\right)\left(2\right)\right)$ 
$\left(11\right)$ $3tan^{2}θ+2=3$ 
$\left(111\right)cos^{2}θ$ $11rac\left(1\right)\left(4\right)\right)=$ 
$c\left(1\right)\left(4\right)\right)=11113c\left(1\right)\left(2\right)\right)$
10th-13th grade
Trigonometry
search-thumbnail-Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
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