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Formula
Solve the equation
Answer
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$y = \dfrac { 1 } { 2 } x + \dfrac { 4 } { 3 } x$
$y = 33$
$x$-intercept
$\left ( 0 , 0 \right )$
$y$-intercept
$\left ( 0 , 0 \right )$
$\dfrac{ 1 }{ 2 } x+ \dfrac{ 4 }{ 3 } x = 33$
$x = 18$
$ $ Solve a solution to $ x$
$\color{#FF6800}{ \dfrac { 1 } { 2 } } \color{#FF6800}{ x } + \dfrac { 4 } { 3 } x = 33$
$ $ Calculate the multiplication expression $ $
$\color{#FF6800}{ \dfrac { x } { 2 } } + \dfrac { 4 } { 3 } x = 33$
$\dfrac { x } { 2 } + \color{#FF6800}{ \dfrac { 4 } { 3 } } \color{#FF6800}{ x } = 33$
$ $ Calculate the multiplication expression $ $
$\dfrac { x } { 2 } + \color{#FF6800}{ \dfrac { 4 x } { 3 } } = 33$
$\color{#FF6800}{ \dfrac { x } { 2 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 4 x } { 3 } } = 33$
$ $ Write all numerators above the least common denominator $ $
$\color{#FF6800}{ \dfrac { 3 x + 8 x } { 6 } } = 33$
$\dfrac { \color{#FF6800}{ 3 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 8 } \color{#FF6800}{ x } } { 6 } = 33$
$ $ Calculate between similar terms $ $
$\dfrac { \color{#FF6800}{ 11 } \color{#FF6800}{ x } } { 6 } = 33$
$\color{#FF6800}{ \dfrac { 11 x } { 6 } } = \color{#FF6800}{ 33 }$
$ $ Multiply both sides by the least common multiple for the denominators to eliminate the fraction $ $
$\color{#FF6800}{ 11 } \color{#FF6800}{ x } = \color{#FF6800}{ 198 }$
$\color{#FF6800}{ 11 } \color{#FF6800}{ x } = \color{#FF6800}{ 198 }$
$ $ Divide both sides by the same number $ $
$\color{#FF6800}{ x } = \color{#FF6800}{ 18 }$
$ $ 그래프 보기 $ $
Graph
Solution search results
search-thumbnail-$\dfrac {4} {3}x+7$ 
$\dfrac {5} {6}x+7$ $\dfrac {1} {2}x+2$
7th-9th grade
Algebra
search-thumbnail-Question $4$ 
If $x$ is $6$ what $|s$ 
$\dfrac {1} {3}x$ 
$1frac\left(1\right)\left(3\right)x$
1st-6th grade
Other
search-thumbnail-Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
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