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Formula
Find the sum of the fractions
Answer
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$\dfrac{ 1 }{ 16 } + \dfrac{ 1 }{ 12 }$
$\dfrac { 7 } { 48 }$
Find the sum of the fractions
$\dfrac { 1 } { \color{#FF6800}{ 16 } } + \dfrac { 1 } { \color{#FF6800}{ 12 } }$
$ $ The smallest common multiple in denominator is $ 48$
$\dfrac { 1 } { \color{#FF6800}{ 16 } } + \dfrac { 1 } { \color{#FF6800}{ 12 } }$
$\dfrac { 1 } { 16 } + \dfrac { 1 } { 12 }$
$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $
$\dfrac { 1 \times \color{#FF6800}{ 3 } } { 16 \times \color{#FF6800}{ 3 } } + \dfrac { 1 \times \color{#FF6800}{ 4 } } { 12 \times \color{#FF6800}{ 4 } }$
$\color{#FF6800}{ \dfrac { 1 \times 3 } { 16 \times 3 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 1 \times 4 } { 12 \times 4 } }$
$ $ Organize the expression $ $
$\color{#FF6800}{ \dfrac { 3 } { 48 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 4 } { 48 } }$
$\color{#FF6800}{ \dfrac { 3 } { 48 } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { 4 } { 48 } }$
$ $ Since the denominator is the same as $ 48 $ , combine the fractions into one $ $
$\color{#FF6800}{ \dfrac { 3 + 4 } { 48 } }$
$\dfrac { \color{#FF6800}{ 3 } \color{#FF6800}{ + } \color{#FF6800}{ 4 } } { 48 }$
$ $ Add $ 3 $ and $ 4$
$\dfrac { \color{#FF6800}{ 7 } } { 48 }$
Solution search results
search-thumbnail-Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8}
7th-9th grade
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