Calculate the value

In the following problem $a,b,$ b,and c represent REAL NUMBERS. 
The derivative of $g\left(x\right)=log _{a}\left(bx\right)+cx^{2}is$ 
$○$ $g^{1}\left(x\right)=\right)dfrac\left(b\right)log _{-}a\left(bx\right)\right)\left(N1n$ $a\right)+2cx1\right)$ 
$○$ $\left(g\left(x\right)=\right)dtracb$ $loga\left(bx\right)+2c\times \right)Nln$ a}\) 
$○$ $g^{'}\left(x\right)=\left(dfraC\left(a\right)log _{-}a\left(bx\right)\right)\left(ln$ $\right)+2c\times 1\right)\right)$ 
$○$ $g^{1}\left(x\right)=\left(dfrac\left(b$ $log _{-}a\left(bx\right)\right)\left(ln$ $a1\right)$ 
$○$ $\left(\left(g^{1}\left(x\right)=b$ $log _{-}a\left(bx\right)+2cx1\right)$ 
$○$ $g\left(x\right)=\left(dfrac\left(b$ $log _{-}a\left(bx\right)\right)\left(1ln$ $a|+2c1\right)$ 

What is the inverse of $g\left(x\right)=\sqrt{x-1} $ 
$Og\left(x\right)=\sqrt{x+1} $ 
$+1$ $g^{'}\left(x\right)=5-$ $y_{9}$ $g\sqrt{ef\left(x\left(nght\right)} =\left(f_{tac\left(x+1\right)0sq\pi \left(x\right)}$ 
$Og^{'}\left(x\right)=x^{2}+1$ 
$○g\left(x\right)=x^{2}-1$ 
« Previous Ne 

$5.\left($ Given that $A=\left(\left(x,y\right)|x^{2}+2y^{2}=3\right)$ and $B=\left(\left(x,y\right)|mx+c\right)$ If $A∩B≠q$ for all $A∈R,$ then range 
of 'c' is 
$1\right)$ $-\dfrac {\sqrt{6} } {2},\dfrac {\sqrt{6} } {2}\right)$ $2\right)\left(-\dfrac {\sqrt{6} } {2},\dfrac {\sqrt{6} } {2}\right)$ $3\right)\left(-\dfrac {\sqrt{6} } {2}\dfrac {\sqrt{6} } {2}\right)$ $4\right)$ $-\dfrac {2\sqrt{3} } {3},\dfrac {2\sqrt{3} } {3}\right)$ 

cos 255° 
$O$ $\dfrac {-\sqrt{2} -\sqrt{6} } {4}$ 
$O$ $\dfrac {\sqrt{2} -\sqrt{6} } {4}$ 
$O$ $\dfrac {\sqrt{2} -\sqrt{6} } {2}$ 
$O$ $\dfrac {\sqrt{6} -\sqrt{2} } {2}$ 

The rationalizing factor of \sqrt{23} is 
$°$ $Options^{°}$ $0$ 
A 24 
23 
C \sqrt{23} 
D None of these 

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