Calculate the value

Simplify $\left(\dfrac {2^{5}} {3^{2}}\right)^{4}$ 
$O\dfrac {2^{0}} {3^{8}}$ 
$O$ $\dfrac {2^{9}} {3^{8}}$ 
$O\dfrac {8^{5}} {12^{2}}$ 
$O\dfrac {2} {3^{2}}$ 

Simplify $\left(\dfrac {2^{5}} {3^{2}}\right)^{4}$ 
$O\dfrac {2^{20}} {3^{8}}$ 
$O\dfrac {2^{9}} {3^{8}}$ 
$O\dfrac {8^{5}} {12^{2}}$ 
$O\dfrac {2} {3^{2}}$ 

In the following problem $a,b,$ b,and c represent REAL NUMBERS. 
The derivative of $g\left(x\right)=log _{a}\left(bx\right)+cx^{2}is$ 
$○$ $g^{1}\left(x\right)=\right)dfrac\left(b\right)log _{-}a\left(bx\right)\right)\left(N1n$ $a\right)+2cx1\right)$ 
$○$ $\left(g\left(x\right)=\right)dtracb$ $loga\left(bx\right)+2c\times \right)Nln$ a}\) 
$○$ $g^{'}\left(x\right)=\left(dfraC\left(a\right)log _{-}a\left(bx\right)\right)\left(ln$ $\right)+2c\times 1\right)\right)$ 
$○$ $g^{1}\left(x\right)=\left(dfrac\left(b$ $log _{-}a\left(bx\right)\right)\left(ln$ $a1\right)$ 
$○$ $\left(\left(g^{1}\left(x\right)=b$ $log _{-}a\left(bx\right)+2cx1\right)$ 
$○$ $g\left(x\right)=\left(dfrac\left(b$ $log _{-}a\left(bx\right)\right)\left(1ln$ $a|+2c1\right)$ 

What is the inverse of $g\left(x\right)=\sqrt{x-1} $ 
$Og\left(x\right)=\sqrt{x+1} $ 
$+1$ $g^{'}\left(x\right)=5-$ $y_{9}$ $g\sqrt{ef\left(x\left(nght\right)} =\left(f_{tac\left(x+1\right)0sq\pi \left(x\right)}$ 
$Og^{'}\left(x\right)=x^{2}+1$ 
$○g\left(x\right)=x^{2}-1$ 
« Previous Ne 

$10.000729\right)^{21}\times \left(0.09\longdiv{}3\right)4$ $=-$ $\left(c\right)$ $\left(A\right)$ $\dfrac {10^{3}} {3^{3}}$ $\left(8\right)$ $\dfrac {10^{5}} {3^{5}}$ $\dfrac {10^{2}} {3^{2}}$ (D) $\dfrac {10^{5}} {3^{5}}$ 
$-$ $\bar{=} $ 

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