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$\dfrac{ \sqrt{ 3 } +2 }{ \sqrt{ 3 } -2 }$
$- 7 - 4 \sqrt{ 3 }$
Calculate the value
$\dfrac { \sqrt{ 3 } + 2 } { \sqrt{ 3 } - 2 }$
$ $ Find the conjugate irrational number of denominator $ $
$\color{#FF6800}{ \dfrac { \sqrt{ 3 } + 2 } { \sqrt{ 3 } - 2 } } \color{#FF6800}{ \times } \color{#FF6800}{ \dfrac { \sqrt{ 3 } + 2 } { \sqrt{ 3 } + 2 } }$
$\dfrac { \sqrt{ 3 } + 2 } { \sqrt{ 3 } - 2 } \times \dfrac { \sqrt{ 3 } + 2 } { \sqrt{ 3 } + 2 }$
$ $ The denominator is multiplied by denominator, and the numerator is multiplied by numerator $ $
$\color{#FF6800}{ \dfrac { \left ( \sqrt{ 3 } + 2 \right ) \left ( \sqrt{ 3 } + 2 \right ) } { \left ( \sqrt{ 3 } - 2 \right ) \left ( \sqrt{ 3 } + 2 \right ) } }$
$\dfrac { \left ( \sqrt{ \color{#FF6800}{ 3 } } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \right ) \left ( \sqrt{ \color{#FF6800}{ 3 } } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \right ) } { \left ( \sqrt{ 3 } - 2 \right ) \left ( \sqrt{ 3 } + 2 \right ) }$
$ $ Expand using $ \left(a + b\right)\left(c + d\right) = ac + ad + bc + bd$
$\dfrac { \sqrt{ \color{#FF6800}{ 3 } } \sqrt{ \color{#FF6800}{ 3 } } \color{#FF6800}{ + } \sqrt{ \color{#FF6800}{ 3 } } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 3 } } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } } { \left ( \sqrt{ 3 } - 2 \right ) \left ( \sqrt{ 3 } + 2 \right ) }$
$\dfrac { \sqrt{ 3 } \sqrt{ 3 } + \sqrt{ 3 } \times 2 + 2 \sqrt{ 3 } + 2 \times 2 } { \left ( \sqrt{ \color{#FF6800}{ 3 } } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \right ) \left ( \sqrt{ \color{#FF6800}{ 3 } } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \right ) }$
$ $ Expand the expression using $ \left(a - b\right)\left(a + b\right) = a^{2} - b^{2}$
$\dfrac { \sqrt{ 3 } \sqrt{ 3 } + \sqrt{ 3 } \times 2 + 2 \sqrt{ 3 } + 2 \times 2 } { \left ( \sqrt{ \color{#FF6800}{ 3 } } \right ) ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 2 } } }$
$\dfrac { \sqrt{ \color{#FF6800}{ 3 } } \sqrt{ \color{#FF6800}{ 3 } } + \sqrt{ 3 } \times 2 + 2 \sqrt{ 3 } + 2 \times 2 } { \left ( \sqrt{ 3 } \right ) ^ { 2 } - 2 ^ { 2 } }$
$ $ Arrange the expression $ $
$\dfrac { \sqrt{ \color{#FF6800}{ 3 } \color{#FF6800}{ \times } \color{#FF6800}{ 3 } } + \sqrt{ 3 } \times 2 + 2 \sqrt{ 3 } + 2 \times 2 } { \left ( \sqrt{ 3 } \right ) ^ { 2 } - 2 ^ { 2 } }$
$\dfrac { \sqrt{ 3 \times 3 } + \sqrt{ 3 } \times 2 + 2 \sqrt{ 3 } + 2 \times 2 } { \left ( \sqrt{ \color{#FF6800}{ 3 } } \right ) ^ { \color{#FF6800}{ 2 } } - 2 ^ { 2 } }$
$ $ Calculate power $ $
$\dfrac { \sqrt{ 3 \times 3 } + \sqrt{ 3 } \times 2 + 2 \sqrt{ 3 } + 2 \times 2 } { \color{#FF6800}{ 3 } - 2 ^ { 2 } }$
$\dfrac { \sqrt{ 3 \times 3 } + \sqrt{ 3 } \times 2 + 2 \sqrt{ 3 } + 2 \times 2 } { 3 - \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 2 } } }$
$ $ Calculate power $ $
$\dfrac { \sqrt{ 3 \times 3 } + \sqrt{ 3 } \times 2 + 2 \sqrt{ 3 } + 2 \times 2 } { 3 - \color{#FF6800}{ 4 } }$
$\dfrac { \sqrt{ \color{#FF6800}{ 3 } \color{#FF6800}{ \times } \color{#FF6800}{ 3 } } + \sqrt{ 3 } \times 2 + 2 \sqrt{ 3 } + 2 \times 2 } { 3 - 4 }$
$ $ Multiply $ 3 $ and $ 3$
$\dfrac { \sqrt{ \color{#FF6800}{ 9 } } + \sqrt{ 3 } \times 2 + 2 \sqrt{ 3 } + 2 \times 2 } { 3 - 4 }$
$\dfrac { \sqrt{ 9 } + \sqrt{ \color{#FF6800}{ 3 } } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } + 2 \sqrt{ 3 } + 2 \times 2 } { 3 - 4 }$
$ $ Simplify the expression $ $
$\dfrac { \sqrt{ 9 } + \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 3 } } + 2 \sqrt{ 3 } + 2 \times 2 } { 3 - 4 }$
$\dfrac { \sqrt{ 9 } + 2 \sqrt{ 3 } + 2 \sqrt{ 3 } + \color{#FF6800}{ 2 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } } { 3 - 4 }$
$ $ Multiply $ 2 $ and $ 2$
$\dfrac { \sqrt{ 9 } + 2 \sqrt{ 3 } + 2 \sqrt{ 3 } + \color{#FF6800}{ 4 } } { 3 - 4 }$
$\dfrac { \sqrt{ 9 } + 2 \sqrt{ 3 } + 2 \sqrt{ 3 } + 4 } { \color{#FF6800}{ 3 } \color{#FF6800}{ - } \color{#FF6800}{ 4 } }$
$ $ Subtract $ 4 $ from $ 3$
$\dfrac { \sqrt{ 9 } + 2 \sqrt{ 3 } + 2 \sqrt{ 3 } + 4 } { \color{#FF6800}{ - } \color{#FF6800}{ 1 } }$
$\dfrac { \sqrt{ 9 } + 2 \sqrt{ 3 } + 2 \sqrt{ 3 } + 4 } { \color{#FF6800}{ - } 1 }$
$ $ If the denominator is 1, the denominator can be removed $ $
$\color{#FF6800}{ - } \left ( \sqrt{ \color{#FF6800}{ 9 } } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 3 } } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 3 } } \color{#FF6800}{ + } \color{#FF6800}{ 4 } \right )$
$- \left ( \sqrt{ \color{#FF6800}{ 9 } } + 2 \sqrt{ 3 } + 2 \sqrt{ 3 } + 4 \right )$
$ $ Organize the part that can be taken out of the radical sign inside the square root symbol $ $
$- \left ( \color{#FF6800}{ 3 } + 2 \sqrt{ 3 } + 2 \sqrt{ 3 } + 4 \right )$
$- \left ( \color{#FF6800}{ 3 } + 2 \sqrt{ 3 } + 2 \sqrt{ 3 } \color{#FF6800}{ + } \color{#FF6800}{ 4 } \right )$
$ $ Add $ 3 $ and $ 4$
$- \left ( \color{#FF6800}{ 7 } + 2 \sqrt{ 3 } + 2 \sqrt{ 3 } \right )$
$- \left ( 7 + \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 3 } } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 3 } } \right )$
$ $ Calculate between similar terms $ $
$- \left ( 7 + \color{#FF6800}{ 4 } \sqrt{ \color{#FF6800}{ 3 } } \right )$
$\color{#FF6800}{ - } \left ( \color{#FF6800}{ 7 } \color{#FF6800}{ + } \color{#FF6800}{ 4 } \sqrt{ \color{#FF6800}{ 3 } } \right )$
$ $ Change the symbol of each term in parentheses when there is a (-) symbol in front of parentheses $ $
$\color{#FF6800}{ - } \color{#FF6800}{ 7 } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \sqrt{ \color{#FF6800}{ 3 } }$
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