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Calculate the value
Answer
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$\dfrac{ \sqrt{ 21 } +2 \sqrt{ 5 } }{ \sqrt{ 3 } } + \dfrac{ 4 \sqrt{ 2 } - \sqrt{ 14 } }{ \sqrt{ 2 } }$
$\dfrac { 2 \sqrt{ 15 } + 12 } { 3 }$
Calculate the value
$\color{#FF6800}{ \dfrac { \sqrt{ 21 } + 2 \sqrt{ 5 } } { \sqrt{ 3 } } } + \dfrac { 4 \sqrt{ 2 } - \sqrt{ 14 } } { \sqrt{ 2 } }$
$ $ Calculate the expression $ $
$\color{#FF6800}{ \dfrac { 3 \sqrt{ 7 } + 2 \sqrt{ 15 } } { 3 } } + \dfrac { 4 \sqrt{ 2 } - \sqrt{ 14 } } { \sqrt{ 2 } }$
$\dfrac { 3 \sqrt{ 7 } + 2 \sqrt{ 15 } } { 3 } + \color{#FF6800}{ \dfrac { 4 \sqrt{ 2 } - \sqrt{ 14 } } { \sqrt{ 2 } } }$
$ $ Calculate the expression $ $
$\dfrac { 3 \sqrt{ 7 } + 2 \sqrt{ 15 } } { 3 } + \color{#FF6800}{ \dfrac { 8 - \left ( 2 \sqrt{ 7 } \right ) } { 2 } }$
$\dfrac { 3 \sqrt{ 7 } + 2 \sqrt{ 15 } } { 3 } + \dfrac { 8 \color{#FF6800}{ - } \left ( \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 7 } } \right ) } { 2 }$
$ $ Get rid of unnecessary parentheses $ $
$\dfrac { 3 \sqrt{ 7 } + 2 \sqrt{ 15 } } { 3 } + \dfrac { 8 \color{#FF6800}{ - } \color{#FF6800}{ 2 } \sqrt{ \color{#FF6800}{ 7 } } } { 2 }$
$\dfrac { 3 \sqrt{ 7 } + 2 \sqrt{ 15 } } { 3 } + \color{#FF6800}{ \dfrac { 8 - 2 \sqrt{ 7 } } { 2 } }$
$ $ Reduce the fraction $ $
$\dfrac { 3 \sqrt{ 7 } + 2 \sqrt{ 15 } } { 3 } + \color{#FF6800}{ 4 } \color{#FF6800}{ - } \sqrt{ \color{#FF6800}{ 7 } }$
$\color{#FF6800}{ \dfrac { 3 \sqrt{ 7 } + 2 \sqrt{ 15 } } { 3 } } \color{#FF6800}{ + } \color{#FF6800}{ 4 } - \sqrt{ 7 }$
$ $ Find the sum of the fractions $ $
$\color{#FF6800}{ \dfrac { 3 \sqrt{ 7 } + 2 \sqrt{ 15 } + 12 } { 3 } } - \sqrt{ 7 }$
$\color{#FF6800}{ \dfrac { 3 \sqrt{ 7 } + 2 \sqrt{ 15 } + 12 } { 3 } } \color{#FF6800}{ - } \sqrt{ \color{#FF6800}{ 7 } }$
$ $ Find the sum of the fractions $ $
$\color{#FF6800}{ \dfrac { 3 \sqrt{ 7 } + 2 \sqrt{ 15 } + 12 - 3 \sqrt{ 7 } } { 3 } }$
$\dfrac { \color{#FF6800}{ 3 } \sqrt{ \color{#FF6800}{ 7 } } + 2 \sqrt{ 15 } + 12 \color{#FF6800}{ - } \color{#FF6800}{ 3 } \sqrt{ \color{#FF6800}{ 7 } } } { 3 }$
$ $ Eliminate opponent number $ $
$\dfrac { 2 \sqrt{ 15 } + 12 } { 3 }$
Solution search results
search-thumbnail-The rationalizing factor of \sqrt{23} is 
$°$ $Options^{°}$ $0$ 
A 24 
23 
C \sqrt{23} 
D None of these
7th-9th grade
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