Learn

Logarithm Essentials: Definition, Properties, and Calculations

2026.04.24

by QANDA

Math study
Math study

Logarithms are the inverse of exponentiation and one of the most frequently tested concepts in high school math. They go hand-in-hand with exponential functions and appear throughout algebra and calculus.

πŸ’‘
Logarithms appear in 2–3 questions on most standardized math exams. Master the definition and the three key laws, and you can solve the vast majority of log problems.

What Is a Logarithm?

Definition

A logarithm answers the question: "How many times must I multiply the base to get this number?"

For a>0a > 0, aβ‰ 1a \neq 1, and N>0N > 0, if ax=Na^x = N then x=log⁑aNx = \log_a N.

log⁑aN=xβ€…β€ŠβŸΊβ€…β€Šax=N\log_a N = x \iff a^x = N

Here aa is the base and NN is the argument.

Conditions for a Valid Logarithm

A logarithm log⁑aN\log_a N is defined only when:

  1. Base condition: a>0a > 0 and a≠1a \neq 1
  2. Argument condition: N>0N > 0
  3. If either condition fails, the logarithm is undefined

Common Log vs Natural Log

TypeBaseNotationUse
Common log10log⁑N\log N (base omitted)Digit counting, standardized tests
Natural logeβ‰ˆ2.718e \approx 2.718ln⁑N\ln NCalculus, science

Logarithm Properties and Laws

Step 1: Basic Properties

For any valid base aa:

log⁑a1=0(∡a0=1)\log_a 1 = 0 \quad (\because a^0 = 1)

log⁑aa=1(∡a1=a)\log_a a = 1 \quad (\because a^1 = a)

alog⁑aN=Na^{\log_a N} = N

Step 2: The Three Laws of Logarithms

For M>0M > 0 and N>0N > 0:

Law 1 β€” Product β†’ Addition

log⁑aMN=log⁑aM+log⁑aN\log_a MN = \log_a M + \log_a N

Law 2 β€” Quotient β†’ Subtraction

log⁑aMN=log⁑aMβˆ’log⁑aN\log_a \frac{M}{N} = \log_a M - \log_a N

Law 3 β€” Power β†’ Multiplication

log⁑aMk=klog⁑aM\log_a M^k = k \log_a M

Step 3: Change of Base Formula

The key formula for converting between different bases:

log⁑ab=log⁑cblog⁑ca\log_a b = \frac{\log_c b}{\log_c a}

Useful variations:

log⁑ab=1log⁑ba\log_a b = \frac{1}{\log_b a}

log⁑abβ‹…log⁑bc=log⁑ac\log_a b \cdot \log_b c = \log_a c

⚠️
The most common mistake is thinking log⁑a(M+N)=log⁑aM+log⁑aN\log_a(M + N) = \log_a M + \log_a N. The product rule only works for multiplication inside the log, not addition!

Advanced: Applications of Logarithms

Finding the Number of Digits

The number of digits in a positive integer NN is ⌊log⁑10NβŒ‹+1\lfloor \log_{10} N \rfloor + 1.

For example, 210=10242^{10} = 1024:

log⁑101024β‰ˆ3.01β‡’βŒŠ3.01βŒ‹+1=4Β digits\log_{10} 1024 \approx 3.01 \Rightarrow \lfloor 3.01 \rfloor + 1 = 4 \text{ digits}


Practice Problems

Example 1: Applying Log Laws

Problem: Find the value of log⁑212βˆ’log⁑23\log_2 12 - \log_2 3.

Show Solution

Apply the quotient rule:

log⁑212βˆ’log⁑23=log⁑2123=log⁑24=2\log_2 12 - \log_2 3 = \log_2 \frac{12}{3} = \log_2 4 = 2

Answer: 22

Example 2: Change of Base

Problem: Find the value of log⁑23Γ—log⁑38\log_2 3 \times \log_3 8.

Show Solution

Use the chain rule for logarithms:

log⁑23Γ—log⁑38=log⁑28=3\log_2 3 \times \log_3 8 = \log_2 8 = 3

Alternatively, log⁑38=3log⁑32\log_3 8 = 3\log_3 2, so:

log⁑23Γ—3log⁑32=3Γ—log⁑23Γ—1log⁑23=3\log_2 3 \times 3\log_3 2 = 3 \times \log_2 3 \times \frac{1}{\log_2 3} = 3

Answer: 33

πŸ“
When solving log problems, always start by unifying the bases and prime-factoring the arguments. Most problems are solved in these two steps.

Top 3 Common Mistakes

  1. Ignoring the argument condition β€” Forgetting to check N>0N > 0 in log⁑aN\log_a N and substituting negative numbers or zero. Always verify the argument after solving.
  2. Confusing addition with multiplication β€” log⁑(M+N)β‰ log⁑M+log⁑N\log(M + N) \neq \log M + \log N. You can only separate logs when the argument is a product.
  3. Swapping numerator and denominator in base change β€” In log⁑ab=log⁑blog⁑a\log_a b = \frac{\log b}{\log a}, bb is in the numerator and aa is in the denominator.

Related Concepts

  • Exponential Functions β€” inverse pair
  • Integration β€” log in calculus
  • Quadratic Equations β€” algebraic foundation